Last visit was: 25 Apr 2024, 03:11 It is currently 25 Apr 2024, 03:11

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618895 [16]
Given Kudos: 81595
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618895 [3]
Given Kudos: 81595
Send PM
Intern
Intern
Joined: 21 Feb 2017
Posts: 1
Own Kudos [?]: 0 [0]
Given Kudos: 2
Location: India
GMAT 1: 710 Q49 V38
GPA: 3.57
Send PM
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618895 [0]
Given Kudos: 81595
Send PM
Re: M12-30 [#permalink]
Expert Reply
Aswath Kumar wrote:
If the constant multiplied is equal to 1, then option 1 also fails.

I am not sure if I am missing something. A constant can be any real integer right?


The mean of four integers will not change if all the integers are multiplied by ANY constant.

Of course the mean won't change if you multiply all the integers by 1 and in this case the mean could be any number but if we want the mean not to change when we multiply by ANY constant than the mean must be 0.

Check for more here: https://gmatclub.com/forum/the-mean-of- ... 70142.html
Intern
Intern
Joined: 30 Aug 2017
Posts: 10
Own Kudos [?]: 1 [0]
Given Kudos: 64
GMAT 1: 700 Q48 V38
Send PM
Re: M12-30 [#permalink]
I think this is a high-quality question and I agree with explanation.
Retired Moderator
Joined: 31 May 2020
Posts: 174
Own Kudos [?]: 926 [0]
Given Kudos: 47
Location: India
Send PM
Re: M12-30 [#permalink]
I think this is a high-quality question and I agree with explanation. A simple but a very good concept question
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618895 [1]
Given Kudos: 81595
Send PM
Re: M12-30 [#permalink]
1
Kudos
Expert Reply
I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
Intern
Intern
Joined: 05 Jul 2023
Posts: 16
Own Kudos [?]: 5 [0]
Given Kudos: 12
Location: India
GMAT 1: 630 Q42 V34
GMAT 2: 710 Q49 V40
GPA: 3.2
Send PM
Re: M12-30 [#permalink]
Hi Bunuel, in the example you have given above, I interpreted it as the largest members being 1 and 2 and the smallest members being -3 and 0. So the sum still comes to be zero which is also what I did during practice. Would it make more sense to say sum of the largest and smallest member is zero, instead of saying members?
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618895 [0]
Given Kudos: 81595
Send PM
Re: M12-30 [#permalink]
Expert Reply
gokusan wrote:
Hi Bunuel, in the example you have given above, I interpreted it as the largest members being 1 and 2 and the smallest members being -3 and 0. So the sum still comes to be zero which is also what I did during practice. Would it make more sense to say sum of the largest and smallest member is zero, instead of saying members?


When referring to the "sum of the largest and smallest members," it typically means considering only one largest number and one smallest number from the list, not multiple. I've never seen any example of the opposite. So, I think the wording is fine as it is.
GMAT Club Bot
Re: M12-30 [#permalink]
Moderator:
Math Expert
92912 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne