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Bunuel
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Bunuel
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I thought the digit 1 is the third from the right of the decimal point. So, if 1 is not the third, in which position is it? Are not the decimal points supposed to be the ones after the comma, in which case 1 would be the third and the 2 zeros would be first and second. I don't understand this concept at all.... Can someone pplease help?!

(2/23)^3 = 0.000657516232431988164707816224213035259307964165365332456... 0 is the third digit to the right of the decimal point.

1 is the third digit to the right of the decimal point of \((\frac{2}{20})^3= 0.001\). Because \((\frac{2}{23})^3 \lt (\frac{2}{20})^3\), then the third digit to the right of the decimal point of (2/23)^3 must be 0.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Using approximation,
(­2/23)^3­
\(\frac{2}{23}\) ~ 0.08
\((0.08)^3\)­
After decimal there are two places, squaring it will make it 4 places,
\((0.0064) * (0.08)\)­
Now multiplying it by 0.08 will make it 6 places after decimal,
0.000512­
Therefore, third place after decimal will be 0­
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Hahahaha I was sitting here trying to do long division. Big mistake, great explanation and good question on estimate and number properties

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I like the solution - it’s helpful.
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