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M17-21

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M17-21  [#permalink]

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New post 16 Sep 2014, 00:01
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

91% (00:43) correct 9% (00:42) wrong based on 238 sessions

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Re M17-21  [#permalink]

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New post 16 Sep 2014, 00:01
Official Solution:

\(\frac{1}{12}\) is what percent smaller than \(\frac{1}{3}\)?

A. 55%
B. 60%
C. 72%
D. 75%
E. 80%

\((\frac{\frac{1}{3} - \frac{1}{12}}{\frac{1}{3}})*100\% = (\frac{\frac{3}{12}}{\frac{1}{3}})*100\% = (\frac{3}{4})*100\% = 75\%\).

Answer: D
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M17-21  [#permalink]

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New post 31 Aug 2015, 20:23
another way to solve
1/12 is 1/4 of (1/3).

Lets have a parallel example now to understand the difference..
25 is 1/4 of 100. 25 is less than 100 by 75...
hence 1/12 is 75% less than 1/3
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Re: M17-21  [#permalink]

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New post 09 May 2017, 06:55
The question is asking us to find the percentage of (1/3-1/12) w.r.t 1/3. Solving , we get 3/4 or 75%
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Re: M17-21  [#permalink]

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New post 09 May 2017, 22:32
1
1/3-1/12= 4-1/12
3/12= 1/4
1/4=25%.
Difference between 1/3 and 1/12 is 25% and hence 1/12 is 75% smaller than 1/3
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Re: M17-21  [#permalink]

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New post 29 Jun 2017, 20:35
= 1 - (1/12)/(1/3)

Using the reciprocal

= 1 - (1/12)*(3/1)
= 1 - 3/12
= 1 - 1/4
= 3/4
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Re: M17-21  [#permalink]

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New post 14 Sep 2017, 16:01
1
1/3 - x/100(1/3) = 1/12

1-x/100 = 1/4

x=75
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Re: M17-21  [#permalink]

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New post 09 Apr 2018, 11:07
according to the question,
\(1/12\)+\(x/100\)=\(1/3\)
so x = 25.
ans.

where am I going wrong?
please explain.
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Re: M17-21 &nbs [#permalink] 09 Apr 2018, 11:07
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