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# M17-21

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Math Expert
Joined: 02 Sep 2009
Posts: 51184

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16 Sep 2014, 00:01
00:00

Difficulty:

5% (low)

Question Stats:

91% (00:43) correct 9% (00:42) wrong based on 238 sessions

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$$\frac{1}{12}$$ is what percent smaller than $$\frac{1}{3}$$?

A. 55%
B. 60%
C. 72%
D. 75%
E. 80%

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Math Expert
Joined: 02 Sep 2009
Posts: 51184

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16 Sep 2014, 00:01
Official Solution:

$$\frac{1}{12}$$ is what percent smaller than $$\frac{1}{3}$$?

A. 55%
B. 60%
C. 72%
D. 75%
E. 80%

$$(\frac{\frac{1}{3} - \frac{1}{12}}{\frac{1}{3}})*100\% = (\frac{\frac{3}{12}}{\frac{1}{3}})*100\% = (\frac{3}{4})*100\% = 75\%$$.

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Joined: 24 Nov 2013
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31 Aug 2015, 20:23
another way to solve
1/12 is 1/4 of (1/3).

Lets have a parallel example now to understand the difference..
25 is 1/4 of 100. 25 is less than 100 by 75...
hence 1/12 is 75% less than 1/3
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Location: India
GMAT 1: 640 Q48 V29
GMAT 2: 700 Q48 V38
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09 May 2017, 06:55
The question is asking us to find the percentage of (1/3-1/12) w.r.t 1/3. Solving , we get 3/4 or 75%
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Joined: 13 Dec 2016
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09 May 2017, 22:32
1
1/3-1/12= 4-1/12
3/12= 1/4
1/4=25%.
Difference between 1/3 and 1/12 is 25% and hence 1/12 is 75% smaller than 1/3
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Joined: 17 Oct 2016
Posts: 4

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29 Jun 2017, 20:35
= 1 - (1/12)/(1/3)

Using the reciprocal

= 1 - (1/12)*(3/1)
= 1 - 3/12
= 1 - 1/4
= 3/4
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Joined: 14 Mar 2016
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14 Sep 2017, 16:01
1
1/3 - x/100(1/3) = 1/12

1-x/100 = 1/4

x=75
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09 Apr 2018, 11:07
according to the question,
$$1/12$$+$$x/100$$=$$1/3$$
so x = 25.
ans.

where am I going wrong?
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Re: M17-21 &nbs [#permalink] 09 Apr 2018, 11:07
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# M17-21

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