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30 Jun 2010, 10:38
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
52% (02:35) correct
48%
(02:22)
wrong
based on 1062
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The sequence \(a_1\), \(a_2\), \(a_3\), ..., \(a_n\), ... is such that \(i*a_i=j*a_j\) for any pair of positive integers \((i, j)\). If \(a_1\) is a positive integer, which of the following could be true?
I. \(2*a_{100}=a_{99}+a_{98}\)
II. \(a_1\) is the only integer in the sequence
III. The sequence does not contain negative numbers
A. I only
B. II only
C. I and III only
D. II and III only
E. I, II, and III
M17-25
I. \(2*a_{100}=a_{99}+a_{98}\)
II. \(a_1\) is the only integer in the sequence
III. The sequence does not contain negative numbers
A. I only
B. II only
C. I and III only
D. II and III only
E. I, II, and III
M17-25
Series 
is such that 
for any pair of positive integers 
. If 
is a positive integer, which of the following is possible?
I.
II. is the only integer in the series
III. The series does not contain negative numbers
A. I only
B. II only
C. I and III only
D. II and III only
E. I, II, and III
I.
II.
III. The series does not contain negative numbers
A. I only
B. II only
C. I and III only
D. II and III only
E. I, II, and III
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07 Jul 2010, 17:49
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The sequence \(a_1\), \(a_2\), \(a_3\), ..., \(a_n\), ... is such that \(i*a_i=j*a_j\) for any pair of positive integers \((i, j)\). If \(a_1\) is a positive integer, which of the following could be true?
I. \(2*a_{100}=a_{99}+a_{98}\)
II. \(a_1\) is the only integer in the sequence
III. The sequence does not contain negative numbers
A. I only
B. II only
C. I and III only
D. II and III only
E. I, II, and III
Given that the sequence of numbers \(a_1\), \(a_2\), \(a_3\), ... has the following properties: \(i*a_i=j*a_j\) and \(a_1=\text{positive integer}\). Thus, \(1*a_1=2*a_2=3*a_3=4*a_4=5*a_5=...=\text{positive integer}\).
We need to determine which of the given options can occur (note that the question asks which of the following COULD be true, not MUST be true).
I. \(2a_{100}=a_{99}+a_{98}\). Since \(100a_{100}=99a_{99}=98a_{98}\), then \(2a_{100}=\frac{100}{99}a_{100}+\frac{100}{98}a_{100}\). Divide by \(a_{100}\): \(2=\frac{100}{99}+\frac{100}{98}\), which is not true. Hence this option could NOT be true.
II. \(a_1\) is the only integer in the sequence. If \(a_1=1\), then all other terms will be non-integers, because in this case, we would have \(a_1=1=2a_2=3a_3=...\), which leads to \(a_2=\frac{1}{2}\), \(a_3=\frac{1}{3}\), \(a_4=\frac{1}{4}\), and so on. Hence this option could be true.
III. The sequence does not contain negative numbers. Given that \(a_1=\text{positive integer}=n*a_n\), then \(a_n=\frac{\text{positive integer}}{n}=\text{positive number}\). Therefore, this option is always true.
Answer: D
Hope it's clear.
I. \(2*a_{100}=a_{99}+a_{98}\)
II. \(a_1\) is the only integer in the sequence
III. The sequence does not contain negative numbers
A. I only
B. II only
C. I and III only
D. II and III only
E. I, II, and III
Given that the sequence of numbers \(a_1\), \(a_2\), \(a_3\), ... has the following properties: \(i*a_i=j*a_j\) and \(a_1=\text{positive integer}\). Thus, \(1*a_1=2*a_2=3*a_3=4*a_4=5*a_5=...=\text{positive integer}\).
We need to determine which of the given options can occur (note that the question asks which of the following COULD be true, not MUST be true).
I. \(2a_{100}=a_{99}+a_{98}\). Since \(100a_{100}=99a_{99}=98a_{98}\), then \(2a_{100}=\frac{100}{99}a_{100}+\frac{100}{98}a_{100}\). Divide by \(a_{100}\): \(2=\frac{100}{99}+\frac{100}{98}\), which is not true. Hence this option could NOT be true.
II. \(a_1\) is the only integer in the sequence. If \(a_1=1\), then all other terms will be non-integers, because in this case, we would have \(a_1=1=2a_2=3a_3=...\), which leads to \(a_2=\frac{1}{2}\), \(a_3=\frac{1}{3}\), \(a_4=\frac{1}{4}\), and so on. Hence this option could be true.
III. The sequence does not contain negative numbers. Given that \(a_1=\text{positive integer}=n*a_n\), then \(a_n=\frac{\text{positive integer}}{n}=\text{positive number}\). Therefore, this option is always true.
Answer: D
Hope it's clear.
07 Feb 2012, 04:39
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LalaB
Sure.
Given: \(a_1=positive \ integer\). Next, \(i*a_i=j*a_j\), notice that we have the same multiple and the same index of a on both sides: \(1*a_1=2*a_2\), \(2*a_2=3*a_3\), \(a_3=4*a_4\).... Hence, \(1*a_1=2*a_2=3*a_3=4*a_4=5*a_5=...=positive \ integer\) (it equal to an integer since \(a_1=positive \ integer\)).
Hope it's clear.
)
