Official Solution: Initially, 1000 dollars were converted into pounds, and then the pounds were converted back into dollars at the same exchange rate of \(x\) pounds per dollar. If a commission of \(y\%\) is charged on each exchange operation, what is the remaining dollar amount after both exchanges? Note that, \(x\) pounds = 1 dollar, means that 1 pound = \(\frac{1}{x}\) dollars (for example, if 0.5 pounds = 1 dollar, then 1 pound = 1/0.5 = 2 dollars.)
First, when 1000 dollars are converted into pounds at \(x\) pounds per dollar, with a commission of \(y\%\), we get \(1000*x*(1 - \frac{y}{100})\) pounds. Then, when \(1000*x*(1 - \frac{y}{100})\) pounds are converted back into dollars at \(\frac{1}{x}\) dollars per pound, with a commission of \(y\%\), we get \(1000*x*(1 - \frac{y}{100})*\frac{1}{x}*(1 - \frac{y}{100})=1000(1 - \frac{y}{100})^2\). As we can see, since we convert twice at the same exchange rate, the exchange rate does not matter, and only the commission is important. So, to answer the question, we can ignore \(x\) and are interested only in the value of \(y\).
(1) \(x = 0.6\)
The statement above tells us the value of \(x\), not \(y\). Not sufficient.
(2) \(y = 5\)
The statement above tells us the value of \(y\). Sufficient.
Answer: B