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How is a circle derived from any of this info? I see some comments saying x^2+y^2=1, but how is a circle derived from this?
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Circle on a plane
In an x-y Cartesian coordinate system, the circle with center (a, b) and radius r is the set of all points (x, y) such that: \((x-a)^2+(y-b)^2=r^2\)
This equation of the circle follows from the Pythagorean theorem applied to any point on the circle: as shown in the diagram above, the radius is the hypotenuse of a right-angled triangle whose other sides are of length x-a and y-b.
If the circle is centered at the origin (0, 0), then the equation simplifies to: \(x^2+y^2=r^2\)
x^2+y^2=1. x^2= 1-y^2 and y^2=1-^x2. Therefore, 1-y^2>0 and 1-x^2>0 thus -1<x<1 and -1<y<1. Therefore 0<x+1<2.
--------|------------|----- 0 x+1 2 ----|--------|----- -1 y 1
around 1/2 of the time x+1 is always greater than y. for the other 1/2 there is a 1/2 chance that x+1>y or 1/4 chance. So a total of 1/2+1/4 =3/4 chance that x+1>y or 1/4 chance y<x+1
Is the domain of this question is Geometry or Probability... means whether such type of questions can still be tested under new Gmat syllabus..?? I got this question in Gmat club test..
Is the domain of this question is Geometry or Probability... means whether such type of questions can still be tested under new Gmat syllabus..?? I got this question in Gmat club test..
Note that while Geometry is not tested on GMAT Focus, Coordinate Geometry is tested under the Functions and Graphing sections found in the Official Guide for GMAT Focus Edition.
This is a combination of Graphing and Probability - both included topics. If you are aiming for 705+, you may want to take a look at it.
amitarya
Is the domain of this question is Geometry or Probability... means whether such type of questions can still be tested under new Gmat syllabus..?? I got this question in Gmat club test..