|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
16 Sep 2014, 01:15
Kudos
Bookmarks
If \(x\) is a positive integer, what is the remainder when \(x\) is divided by 3?
(1) The remainder when \(x\) is divided by 4 is 1
(2) The remainder when \(x\) is divided by 7 is 6
(1) The remainder when \(x\) is divided by 4 is 1
(2) The remainder when \(x\) is divided by 7 is 6
16 Sep 2014, 01:15
Kudos
Bookmarks
Official Solution:
If \(x\) is a positive integer, what is the remainder when \(x\) is divided by 3?
(1) The remainder when \(x\) is divided by 4 is 1.
Given: \(x=4q+1\), so \(x\) could be: 1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, ... This information is not sufficient to determine the remainder when \(x\) is divided by 3.
(2) The remainder when \(x\) is divided by 7 is 6.
Given: \(x=7p+6\), so \(x\) could be: 6, 13, 20, 27, 34, 41, ... This information is not sufficient to determine the remainder when \(x\) is divided by 3.
(1)+(2) If \(x=13\) then the remainder is 1 when divided by 3, but if \(x=41\) then the remainder is 2 when divided by 3.Not sufficient.
Answer: E
If \(x\) is a positive integer, what is the remainder when \(x\) is divided by 3?
(1) The remainder when \(x\) is divided by 4 is 1.
Given: \(x=4q+1\), so \(x\) could be: 1, 5, 9, 13, 17, 21, 25, 29, 33, 37, 41, ... This information is not sufficient to determine the remainder when \(x\) is divided by 3.
(2) The remainder when \(x\) is divided by 7 is 6.
Given: \(x=7p+6\), so \(x\) could be: 6, 13, 20, 27, 34, 41, ... This information is not sufficient to determine the remainder when \(x\) is divided by 3.
(1)+(2) If \(x=13\) then the remainder is 1 when divided by 3, but if \(x=41\) then the remainder is 2 when divided by 3.Not sufficient.
Answer: E
General Discussion
Posts: 7
03 Jul 2015, 22:40
Kudos
Bookmarks
Bunuel
Thanks for the explanation Bunuel. I too used the same method.
However, I was wondering if there is any faster method to determine the two numbers (13 and 41).
In the exam, my intent is to save as much time as possible and move on to the next question. In that state of mind, I will be inclined to just test the (say) first 5 numbers of the sequence. In the case of (1) above, that will be just 1, 5, 9, 13, 17
and for (2), this will be 6,13, 20, 27, 34.
Clearly, I will have missed the important numbers (13 and 41) which are key to swinging towards the correct answer.
Any suggestions?
