D is the right answer
y=kx+b
y=x/k - b/k
Since slopes are equal k = 1/k
k^2=1
k=+1 or -1
Therefore |k| = 1 ---> |k|-1 = 0
If k=1 , we knw hw the equs would look like
y=x+b
y=x-b
If k=-1 , then two equations would look like
y = -x + b
y = -x +b
In both the scenarios the co-efficient of x is same , so the lines are parallel , the constant b can be +ve or -ve ....that does not matter . if a line is parallel , it does not mean that the constants must have the same sign . It depends on in which quadrant the lines are . A line passing through 1st and 4th quadrant can be parallel to line passing through 2nd and 3rd quadrant . In such scenarios , the slope of both the lines would be equal BUT NOT the constants......