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09 Jun 2015, 08:18
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If \(\frac{x}{11p}\) is an odd prime number, where \(x\) is a positive integer and \(p\) is a prime number, what is the least value of \(x\)?
A. 22
B. 33
C. 44
D. 66
E. 99
A. 22
B. 33
C. 44
D. 66
E. 99
09 Jun 2015, 08:18
Kudos
Bookmarks
Official Solution:
If \(\frac{x}{11p}\) is an odd prime number, where \(x\) is a positive integer and \(p\) is a prime number, what is the least value of \(x\)?
A. 22
B. 33
C. 44
D. 66
E. 99
Given: \(\frac{x}{11p} = (odd \ prime)\);
This implies \(x = 11p*(odd \ prime)\).
We need to minimize \(x\), so we should minimize \(p\) and (odd prime). Since \(p\) is a prime, then the least value of \(p\) is 2 and the least possible value of (odd prime) is 3. Therefore \(x_{min}=11p*(odd \ prime)=11*2*3=66\).
Answer: D
If \(\frac{x}{11p}\) is an odd prime number, where \(x\) is a positive integer and \(p\) is a prime number, what is the least value of \(x\)?
A. 22
B. 33
C. 44
D. 66
E. 99
Given: \(\frac{x}{11p} = (odd \ prime)\);
This implies \(x = 11p*(odd \ prime)\).
We need to minimize \(x\), so we should minimize \(p\) and (odd prime). Since \(p\) is a prime, then the least value of \(p\) is 2 and the least possible value of (odd prime) is 3. Therefore \(x_{min}=11p*(odd \ prime)=11*2*3=66\).
Answer: D
General Discussion
