Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
May 1212:00 PM EDT
-11:59 PM EDT
Make the most of your break with the most realistic GMAT™ prep. Take up to $700 off select products.
May 1308:30 AM PDT
-09:30 AM PDT
In Episode 4 of our GMAT Ninja CR series, we tackle the most intimidating CR question type: Boldface & "Legalese" questions. If you've ever stared at an answer choice that reads, "The first is a consideration introduced to counter a position that...- May 14
08:30 AM PDT
-09:30 AM PDT
Most GMAT test-takers are intimidated by the hardest GMAT Verbal questions. In this session, Target Test Prep GMAT instructor Erika Tyler-John, a 100th percentile GMAT scorer, will show you how top scorers break down challenging Verbal questions..
30 Nov 2021, 02:25
Kudos
Bookmarks
Three athletes A, B and C run a 1000 m race. When A is at a finish line, B is 50 m left to run and C is 88 m left to run. If all three athletes run at a constant speed, how many meters will C have to run to finish the race when B is at the finish line?
A. \(19\)
B. \(36\)
C. \(38\)
D. \(39\)
E. \(40\)
A. \(19\)
B. \(36\)
C. \(38\)
D. \(39\)
E. \(40\)
30 Nov 2021, 02:25
Kudos
Bookmarks
Official Solution:
Three athletes A, B and C run a 1000 m race. When A is at a finish line, B is 50 m left to run and C is 88 m left to run. If all three athletes run at a constant speed, how many meters will C have to run to finish the race when B is at the finish line?
A. \(19\)
B. \(36\)
C. \(38\)
D. \(39\)
E. \(40\)
By the time A covered 1000 m, B covered 950 m, and C covered 912 m.
The ratio of the distances covered by B and C in the same time period is \(\frac{950}{912}\).
By the time B covered 1000 m, B covered additional 50 m, and C covered additional \(x\) m.
The ratio of the distances covered by B and C in the same time period is \(\frac{50}{x}\).
Since B and C run at constant speeds, then the ratio of the distances covered in the same period of time must be equal:
\(\frac{950}{912}=\frac{50}{x}\);
\(x=48\).
So, when B is at the finish line, C is left to run \(88-48=40\) m.
Answer: E
Three athletes A, B and C run a 1000 m race. When A is at a finish line, B is 50 m left to run and C is 88 m left to run. If all three athletes run at a constant speed, how many meters will C have to run to finish the race when B is at the finish line?
A. \(19\)
B. \(36\)
C. \(38\)
D. \(39\)
E. \(40\)
By the time A covered 1000 m, B covered 950 m, and C covered 912 m.
The ratio of the distances covered by B and C in the same time period is \(\frac{950}{912}\).
By the time B covered 1000 m, B covered additional 50 m, and C covered additional \(x\) m.
The ratio of the distances covered by B and C in the same time period is \(\frac{50}{x}\).
Since B and C run at constant speeds, then the ratio of the distances covered in the same period of time must be equal:
\(\frac{950}{912}=\frac{50}{x}\);
\(x=48\).
So, when B is at the finish line, C is left to run \(88-48=40\) m.
Answer: E
15 Mar 2025, 02:59
Kudos
Bookmarks
This is a high-quality question, and that's for sure, Bunuel , I made it bit elaborate to understand where the ratio comes in first place,
Does this make sense, let me know your thought.
If we count the standard formula for rate problems.
s = v1 *t
(B) 950 = v1 * t
(C) 912 = v2 * t
t = 950/v1
t = 912/v2
=> 950/v1 = 912/v2
v1/v2 = 950/912
We don't know the value of constant speed, right?
For B to complete the remaining 50m
t1 = 50/v1
t1 = x / v2
50/v1 = x/v2
v1/v2 = 50/x
So,
950/912 = 50/x
x = 48
Eventually, the remaining meters to finish for C is 40!
Does this make sense, let me know your thought.
If we count the standard formula for rate problems.
s = v1 *t
(B) 950 = v1 * t
(C) 912 = v2 * t
t = 950/v1
t = 912/v2
=> 950/v1 = 912/v2
v1/v2 = 950/912
We don't know the value of constant speed, right?
For B to complete the remaining 50m
t1 = 50/v1
t1 = x / v2
50/v1 = x/v2
v1/v2 = 50/x
So,
950/912 = 50/x
x = 48
Eventually, the remaining meters to finish for C is 40!
