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MathRevolution
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MathRevolution
The cost, \(c\) and the revenue, \(r\) are related via the equation \(c =ar+b\). By how much is the cost increased if the revenue is increased by \(10?\\
\\
\\
\\
(1)\)a=0.5\((2)\)b=5$


hello,
Is there any simpler approach to this question? It would be of great help in understanding. thank you.

Given equation. C1 = ar + b
when revenue increases by $10, C2 = a(r+10)+b => C2=ar+10a+b
Need to find cost increase. C2-C1= 10a

A gives exactly that.
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I think this the explanation isn't clear enough, please elaborate.
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Given equation. C1 = ar + b
when revenue increases by $10, C2 = a(r+10)+b => C2=ar+10a+b
Need to find cost increase. C2-C1= 10a
option a gives us the value of a while option b gives value of b
as c2 - c1 =10a we want the value of a
this is given by option a as a=0.5
hence c2-c1=0.5*10=5
tada..... :-D :-D :-D
hence
we got the answer
option b giving us the value of b is not of any use
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I think this is a high-quality question. solution is not clear
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I don't agree with the explanation. c = r+b if r = 1 , c doesnt increase by 1 times , their is a factor b which also needs to be taken into acc , eg if b = 2. r =1 then c =3 .
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It shows us this as a 700 level question, but is it really though?
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MathRevolution
The cost, \(c\) and the revenue, \(r\) are related via the equation \(c =ar+b\). By how much is the cost increased if the revenue is increased by \(10?\\
\\
\\
\\
(1)\)a=0.5\((2)\)b=5$

Bunuel

Can you please move this to DS forum and format it as well
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gmat1393
MathRevolution
The cost, \(c\) and the revenue, \(r\) are related via the equation \(c =ar+b\). By how much is the cost increased if the revenue is increased by \(10?\\
\\
\\
\\
(1)\)a=0.5\((2)\)b=5$

Bunuel

Can you please move this to DS forum and format it as well
_____________________
Formatted. Thank you!
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I think this is a high-quality question and I agree with explanation.
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