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M60-03

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Math Revolution GMAT Instructor
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M60-03  [#permalink]

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New post 11 Jun 2018, 02:26
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The cost, \(c\) and the revenue, \(r\) are related via the equation \(c =ar+b\). By how much is the cost increased if the revenue is increased by \(10?



(1)\)a=0.5\((2)\)b=5$

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Math Revolution GMAT Instructor
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Re M60-03  [#permalink]

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New post 11 Jun 2018, 02:26
Official Solution:



Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

The first step of the VA (Variable Approach) method is to modify the original condition and the question, and then recheck the question.

The equation \(c = ar + b\) tells us that the cost is increases by $a when the revenue is increases by 1 dollar.

It follows that the cost is increases by 10a when the revenue is increases by 10 dollars. So, the question is asking for the value of a.

The answer is A.

Answer: A
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Re: M60-03  [#permalink]

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New post 13 Sep 2018, 05:02
MathRevolution wrote:
The cost, \(c\) and the revenue, \(r\) are related via the equation \(c =ar+b\). By how much is the cost increased if the revenue is increased by \(10?



(1)\)a=0.5\((2)\)b=5$



hello,
Is there any simpler approach to this question? It would be of great help in understanding. thank you.
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Re: M60-03  [#permalink]

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New post 29 Sep 2018, 17:50
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Shri15kumar wrote:
MathRevolution wrote:
The cost, \(c\) and the revenue, \(r\) are related via the equation \(c =ar+b\). By how much is the cost increased if the revenue is increased by \(10?



(1)\)a=0.5\((2)\)b=5$



hello,
Is there any simpler approach to this question? It would be of great help in understanding. thank you.


Given equation. C1 = ar + b
when revenue increases by $10, C2 = a(r+10)+b => C2=ar+10a+b
Need to find cost increase. C2-C1= 10a

A gives exactly that.
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Re: M60-03 &nbs [#permalink] 29 Sep 2018, 17:50
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