GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 14 Nov 2018, 20:15

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
• ### Free GMAT Strategy Webinar

November 17, 2018

November 17, 2018

07:00 AM PST

09:00 AM PST

Nov. 17, 7 AM PST. Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

# M70-25

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 50585

### Show Tags

03 Sep 2018, 04:56
00:00

Difficulty:

(N/A)

Question Stats:

75% (00:29) correct 25% (00:00) wrong based on 4 sessions

### HideShow timer Statistics

If each of the children who participated in a party put one card with his or her name on it into a hat, how many children participated in this party?

(1) The probability of pulling out a card with a girl’s name, when picking a card out of the hat at random, was $$\frac{2}{3}$$.

(2) There were 3 boys at the party.

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 50585

### Show Tags

03 Sep 2018, 04:56
Official Solution:

We’ll go for LOGICAL since logic is the first option in Data Sufficiency.

(1) This tells us the ratio between girls and boys. But without any exact numbers to work with, we can’t tell how many children there are. (A) and (D) are eliminated.

(2) We know how many boys there were, but how many girls were there? (B) is eliminated.

Combining (1) and (2) gives us the number of boys, and the ratio of boys to girls – two pieces of information that are enough in order to find the number of girls, and thus the total number of children. (E) is eliminated.

_________________
Intern
Joined: 12 Mar 2018
Posts: 2

### Show Tags

30 Sep 2018, 05:55
How do we know that the ratio is divided in what proportion... there can be 9 students and there can be 18 stufdents Answer should have been E?
Senior Manager
Joined: 08 Jun 2013
Posts: 468
Location: India
GMAT 1: 200 Q1 V1
GPA: 3.82
WE: Engineering (Other)

### Show Tags

30 Sep 2018, 06:10
How do we know that the ratio is divided in what proportion... there can be 9 students and there can be 18 stufdents Answer should have been E?

If each of the children who participated in a party put one card with his or her name on it into a hat, how many children participated in this party?

(1) The probability of pulling out a card with a girl’s name, when picking a card out of the hat at random, was 2/3.

(2) There were 3 boys at the party.

No of Girls = G

No of Boys = B

St 1 : G/(B + G) = 2/3

So not sufficient to calculate B+G.

St 2 : B =3

again not sufficient to calculate B+G.

St 1 and St 2 together :

B =3 so 3G = 2B + 2G = 6 + 2G

Hence G = 6

B + G = 9

Sufficient.

Does this help?
_________________

It seems Kudos button not working correctly with all my posts...

Please check if it is working with this post......

is it?....

Anyways...Thanks for trying

Re: M70-25 &nbs [#permalink] 30 Sep 2018, 06:10
Display posts from previous: Sort by

# M70-25

Moderators: chetan2u, Bunuel

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.