GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 22 Oct 2019, 01:49

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

M70-25

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58410
M70-25  [#permalink]

Show Tags

New post 03 Sep 2018, 05:56
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

100% (00:32) correct 0% (00:00) wrong based on 6 sessions

HideShow timer Statistics

If each of the children who participated in a party put one card with his or her name on it into a hat, how many children participated in this party?



(1) The probability of pulling out a card with a girl’s name, when picking a card out of the hat at random, was \(\frac{2}{3}\).

(2) There were 3 boys at the party.

_________________
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58410
Re M70-25  [#permalink]

Show Tags

New post 03 Sep 2018, 05:56
Official Solution:


We’ll go for LOGICAL since logic is the first option in Data Sufficiency.

(1) This tells us the ratio between girls and boys. But without any exact numbers to work with, we can’t tell how many children there are. (A) and (D) are eliminated.

(2) We know how many boys there were, but how many girls were there? (B) is eliminated.

Combining (1) and (2) gives us the number of boys, and the ratio of boys to girls – two pieces of information that are enough in order to find the number of girls, and thus the total number of children. (E) is eliminated.


Answer: C
_________________
Intern
Intern
avatar
B
Joined: 12 Mar 2018
Posts: 2
Re: M70-25  [#permalink]

Show Tags

New post 30 Sep 2018, 06:55
How do we know that the ratio is divided in what proportion... there can be 9 students and there can be 18 stufdents Answer should have been E?
Director
Director
User avatar
D
Joined: 08 Jun 2013
Posts: 543
Location: France
Schools: INSEAD Jan '19
GMAT 1: 200 Q1 V1
GPA: 3.82
WE: Consulting (Other)
GMAT ToolKit User
Re: M70-25  [#permalink]

Show Tags

New post 30 Sep 2018, 07:10
adityaa098 wrote:
How do we know that the ratio is divided in what proportion... there can be 9 students and there can be 18 stufdents Answer should have been E?


adityaa098

If each of the children who participated in a party put one card with his or her name on it into a hat, how many children participated in this party?



(1) The probability of pulling out a card with a girl’s name, when picking a card out of the hat at random, was 2/3.

(2) There were 3 boys at the party.

No of Girls = G

No of Boys = B

St 1 : G/(B + G) = 2/3

So not sufficient to calculate B+G.

St 2 : B =3

again not sufficient to calculate B+G.

St 1 and St 2 together :

B =3 so 3G = 2B + 2G = 6 + 2G

Hence G = 6

B + G = 9

Sufficient.

Does this help?
_________________
Everything will fall into place…

There is perfect timing for
everything and everyone.
Never doubt, But Work on
improving yourself,
Keep the faith and
Stay ready. When it’s
finally your turn,
It will all make sense.
Intern
Intern
avatar
Joined: 04 Jun 2019
Posts: 1
Re: M70-25  [#permalink]

Show Tags

New post 30 Jul 2019, 00:52
There is a difference in " boys participating in a party" and "boys at a party". Of the 3 boys present, only 2 could have participated!?
GMAT Club Bot
Re: M70-25   [#permalink] 30 Jul 2019, 00:52
Display posts from previous: Sort by

M70-25

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderators: chetan2u, Bunuel






Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne