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# Machine A can process 6000 envelopes in 3 hours. Machines B

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Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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25 Nov 2010, 07:25
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Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes.

A. 2
B. 3
C. 4
D. 6
E. 60/7

[Reveal] Spoiler:
I got this far:

Machine C = 6 hours for 6000 envelopes

Then (1/T) = (1/b) +(1/c)

1/2.5 = (1/b) + (1/6)
b= (30/7) for 6000 envelopes or (60/7) for 12000 envelopes.

Why isnt the answer coming up to exactly 8?

EDITED THE OPTIONS
[Reveal] Spoiler: OA

Last edited by Bunuel on 05 Jun 2013, 23:42, edited 2 times in total.
Edited the options.
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25 Nov 2010, 09:08
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shash wrote:
Machine A can process 6000 envelopes in 3 hours. MAchines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes.

2
3
4
6

I got this far:

Machine C = 6 hours for 6000 envelopes

Then (1/T) = (1/b) +(1/c)

1/2.5 = (1/b) + (1/6)
b= (30/7) for 6000 envelopes or (60/7) for 12000 envelopes.

Why isnt the answer coming up to exactly 8?

I think you did everything right.

Let the time needed for A, B and C working individually to process 6,000 envelopes be $$a$$, $$b$$ and $$c$$ respectively.

Now, as "A can process 6,000 envelopes in 3 hours" then $$a=3$$;

As "B and C working together but independently can process the same number (6,000) of envelopes in 2.5 hours" then $$\frac{1}{b}+\frac{1}{c}=\frac{1}{2.5}=\frac{2}{5}$$;

Also, as "A and C working together but independently process 3000 envelopes in 1 hour", then A and C working together but independently process 2*3,000=6,000 envelopes in 2*1=2 hours: $$\frac{1}{a}+\frac{1}{c}=\frac{1}{2}$$ --> as $$a=3$$ then $$c=6$$;

So, $$\frac{1}{b}+\frac{1}{6}=\frac{2}{5}$$ --> $$b=\frac{30}{7}$$, which means that B produces 6,000 envelopes in 30/7 hours, thus it produces 12,000 envelopes in 60/7 hours.

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25 Nov 2010, 20:11
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shash wrote:
Machine A can process 6000 envelopes in 3 hours. MAchines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes.

2
3
4
6

I got this far:

Machine C = 6 hours for 6000 envelopes

Then (1/T) = (1/b) +(1/c)

1/2.5 = (1/b) + (1/6)
b= (30/7) for 6000 envelopes or (60/7) for 12000 envelopes.

Why isnt the answer coming up to exactly 8?

In work rate questions, generally different people have to complete the same amount of work. In this question, to make it a little tricky, they have given varying amount of work done by the machines.
To make the question straight forward, first thing you can do is make the work the same for all:
Machine A processes 12000 envelopes in - 6 hrs
Machines B and C process 12000 in - 5 hrs
Machines A and C process 12000 in - 4 hrs
I chose to get them all to 12000 since my question has 12000 in it. Also, I easily get rid of all decimals.
Now, I just find 1/6 + 1/c = 1/4 and get c = 12
and 1/b + 1/12 = 1/5 so b = 60/7 hrs
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Manager Joined: 30 Aug 2010 Posts: 91 Location: Bangalore, India Followers: 5 Kudos [?]: 163 [9] , given: 27 Re: Rate Problem [#permalink] ### Show Tags 26 Nov 2010, 03:20 9 This post received KUDOS 1 This post was BOOKMARKED forget abt the variables a,b,c,d.....in this simple problem A - 6000 in 3 hrs ==> 2000 in 1 hr BC- 6000 - in 2.5 hrs == 2400 in 1 hr AC - 3000 in 1 hr take AC -3000 in 1 hr , in which A's contribution is 2000 in 1 hr, hence C's contribution is 1000 in 1 hr take BC -2400 , in which C's contribution is 1000 in 1 hr, hence B's contribution is 1400 in 1 hr. B - 1400 - 1 hr ==> 12000 in 12000/1400 hrs = 60/7 Regards, Murali. Manager Joined: 03 Jun 2009 Posts: 50 Followers: 1 Kudos [?]: 12 [0], given: 7 Re: Rate Problem [#permalink] ### Show Tags 27 Nov 2010, 10:07 1 This post was BOOKMARKED muralimba wrote: forget abt the variables a,b,c,d.....in this simple problem A - 6000 in 3 hrs ==> 2000 in 1 hr BC- 6000 - in 2.5 hrs == 2400 in 1 hr AC - 3000 in 1 hr take AC -3000 in 1 hr , in which A's contribution is 2000 in 1 hr, hence C's contribution is 1000 in 1 hr take BC -2400 , in which C's contribution is 1000 in 1 hr, hence B's contribution is 1400 in 1 hr. B - 1400 - 1 hr ==> 12000 in 12000/1400 hrs = 60/7 Regards, Murali. Adding to Murali's approach.... A = 2000 B+C = 2400 A+C = 3000 => C = 3000-1 = 3000-2000 = 1000 => B = 2400 -C =2400-1000 =1400 hence B can process 1400 Envelopes in 1hour...how much time wud it take B to process 12000 Envelopes = 12000/1400 = 60/7 Manager Joined: 01 Nov 2010 Posts: 181 Location: Zürich, Switzerland Followers: 2 Kudos [?]: 42 [0], given: 20 Re: Rate Problem [#permalink] ### Show Tags 27 Nov 2010, 17:58 1 This post was BOOKMARKED For 1 hour- Machine A rate- 2000 envelopes Machine B+C rate- 2400 envelopes Since A + C = 3000 envelopes A's rate is 2000 envelopes as above, C has a rate of 1000 envelopes per hour. Which makes machine B's rate as 1400 envelopes per hour. Thus, it will take 8 hours to manufacture 12000 envelopes. Answer:-E Math Expert Joined: 02 Sep 2009 Posts: 37109 Followers: 7252 Kudos [?]: 96499 [0], given: 10752 Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink] ### Show Tags 30 May 2013, 04:09 Bumping for review and further discussion*. Get a kudos point for an alternative solution! *New project from GMAT Club!!! Check HERE Theory on work/rate problems: work-word-problems-made-easy-87357.html All DS work/rate problems to practice: search.php?search_id=tag&tag_id=46 All PS work/rate problems to practice: search.php?search_id=tag&tag_id=66 _________________ Verbal Forum Moderator Joined: 10 Oct 2012 Posts: 630 Followers: 82 Kudos [?]: 1136 [1] , given: 136 Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink] ### Show Tags 30 May 2013, 09:50 1 This post received KUDOS shash wrote: Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes. A. 2 B. 3 C. 4 D. 6 E. 8 Machine A takes 3 hours for 6000 envelopes. Thus, Machine A would take exactly 6 hours for 12000 envelopes. Also, we know that machines B and C, working together, can produce the same no of envelopes in 2.5 hours. Thus, if$$r_B$$ and$$r_C$$ are the rates respectively , we know that$$(r_B+r_C)*\frac{5}{2}$$ = 6000 --> $$(r_B+r_C) = 2400$$. Thus, even if we assume that $$r_B$$ = 2000 (which is the same rate as that of Machine A), Machine B would again need 6 hours. However, as$$r_C$$= 1000, we know for sure that$$r_B$$ <2000. Thus, the only option more than 6 hours is E(Assuming that the correct OA is provided with the question). _________________ Current Student Joined: 30 May 2013 Posts: 15 GMAT 1: 680 Q48 V35 Followers: 0 Kudos [?]: 5 [0], given: 2 Re: Rate Problem [#permalink] ### Show Tags 05 Jun 2013, 14:36 Sarang wrote: For 1 hour- Machine A rate- 2000 envelopes Machine B+C rate- 2400 envelopes Since A + C = 3000 envelopes A's rate is 2000 envelopes as above, C has a rate of 1000 envelopes per hour. Which makes machine B's rate as 1400 envelopes per hour. Thus, it will take 8 hours to manufacture 12000 envelopes. Answer:-E I did this but shouldn't the work take 9 hours instead? In 8 hours machine B would have made 1400 * 8 = 11200 envelopes. In order to make 12000 it would require a fraction of an hour to create 200 more envelopes. Am I mistaken? Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7187 Location: Pune, India Followers: 2168 Kudos [?]: 14022 [0], given: 222 Re: Rate Problem [#permalink] ### Show Tags 05 Jun 2013, 23:14 PKPKay wrote: Sarang wrote: For 1 hour- Machine A rate- 2000 envelopes Machine B+C rate- 2400 envelopes Since A + C = 3000 envelopes A's rate is 2000 envelopes as above, C has a rate of 1000 envelopes per hour. Which makes machine B's rate as 1400 envelopes per hour. Thus, it will take 8 hours to manufacture 12000 envelopes. Answer:-E I did this but shouldn't the work take 9 hours instead? In 8 hours machine B would have made 1400 * 8 = 11200 envelopes. In order to make 12000 it would require a fraction of an hour to create 200 more envelopes. Am I mistaken? As mentioned above, the OA is incorrect. In fact, the options are incorrect since none of them is 60/7 hrs (which is the answer). _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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05 Jun 2013, 23:44
PKPKay wrote:
Sarang wrote:
For 1 hour-

Machine A rate- 2000 envelopes
Machine B+C rate- 2400 envelopes
Since A + C = 3000 envelopes A's rate is 2000 envelopes as above, C has a rate of 1000 envelopes per hour.
Which makes machine B's rate as 1400 envelopes per hour.

Thus, it will take 8 hours to manufacture 12000 envelopes.

I did this but shouldn't the work take 9 hours instead?
In 8 hours machine B would have made 1400 * 8 = 11200 envelopes.
In order to make 12000 it would require a fraction of an hour to create 200 more envelopes.
Am I mistaken?

Edited the options.

Check for a solution here: machine-a-can-process-6000-envelopes-in-3-hours-machines-b-105362.html#p823509 or here: machine-a-can-process-6000-envelopes-in-3-hours-machines-b-105362.html#p823655
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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07 Jun 2013, 04:35
How much time should one take in solving these kind of questions which involves though simple yet a lot of calculations?
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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09 Jun 2013, 19:52
samheeta wrote:
How much time should one take in solving these kind of questions which involves though simple yet a lot of calculations?

This can be easily done in under 2 mins. If you look at the explanation provided above:

To make the question straight forward, first thing you can do is make the work the same for all:
Machine A processes 12000 envelopes in - 6 hrs
Machines B and C process 12000 in - 5 hrs
Machines A and C process 12000 in - 4 hrs
I chose to get them all to 12000 since my question has 12000 in it. Also, I easily get rid of all decimals.

Almost no calculations till here

Now, I just find 1/6 + 1/c = 1/4 and get c = 12
and 1/b + 1/12 = 1/5 so b = 60/7 hrs

You should be comfortable with manipulating fractions.
1/c = 1/4 - 1/6 = 2/24 = 1/12
So c = 12 (Finding c should take just a few seconds)

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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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09 Jun 2013, 20:56
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shash wrote:
Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes.

A. 2
B. 3
C. 4
D. 6
E. 60/7

You can either take the amount of work done as the same as Karishma has done or take the work done by each in the same time. I will do the latter

1. Work done in 1 hr by A is 2000 envelopes
2. Work done in 1 hr by A and C is 3000 envelopes
3. So work done in 1 hr by C is 1000 envelopes
4. Work done in 1 hr by B and C is 2400 envelopes
5. So work done in 1 hr by B is 1400 envelopes
6. So to process 12000 envelopes B will take 12000/1400 hrs = 60/7 hrs

So the answer is choice E
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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17 Jun 2014, 08:27
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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05 Dec 2014, 01:30
shash wrote:
... If Machines A and C working together but independently ...

Is this a tricky way of saying "working together"? I mean, can I treat that phrase just like how you would when you combine the rates of machine A and machine C? Is there a question where GMAT asks two or more entities working together depending on each other?
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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05 Dec 2014, 06:51
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Blackbox wrote:
shash wrote:
... If Machines A and C working together but independently ...

Is this a tricky way of saying "working together"? I mean, can I treat that phrase just like how you would when you combine the rates of machine A and machine C? Is there a question where GMAT asks two or more entities working together depending on each other?

Yes. This means that they work independently of each other but they are turned on simultaneously.
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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14 Feb 2015, 08:45
shash wrote:
Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes.

A. 2
B. 3
C. 4
D. 6
E. 60/7

[Reveal] Spoiler:
I got this far:

Machine C = 6 hours for 6000 envelopes

Then (1/T) = (1/b) +(1/c)

1/2.5 = (1/b) + (1/6)
b= (30/7) for 6000 envelopes or (60/7) for 12000 envelopes.

Why isnt the answer coming up to exactly 8?

EDITED THE OPTIONS

1/A = 2000

1/B+1/C = 6000/2.5=2400 ---------(1)
1/A+ 1/C = 3000 -----------------------(2)

(1) - (2)
1/B-1/A =2400-3000
> 1/B - 2000 = 2400-3000
> 1/B = 1400

Rate = 1400
Work= 12000

Time= 12000/1400 =60/7

Feed me kudos if it is helpful for you :D
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B [#permalink]

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24 Dec 2015, 15:54
shash wrote:
Machine A can process 6000 envelopes in 3 hours. Machines B and C working together but independently can process the same number of envelopes in 2.5 hours. If Machines A and C working together but independently process 3000 envelopes in 1 hour, then how many hours would it take Machine B to process 12000 envelopes.

A. 2
B. 3
C. 4
D. 6
E. 60/7

[Reveal] Spoiler:
I got this far:

Machine C = 6 hours for 6000 envelopes

Then (1/T) = (1/b) +(1/c)

1/2.5 = (1/b) + (1/6)
b= (30/7) for 6000 envelopes or (60/7) for 12000 envelopes.

Why isnt the answer coming up to exactly 8?

EDITED THE OPTIONS

This is not the original question. In the original question (from Kaplan) the time given for mashines B and C working together is 2\frac{2}{5} and the correct answer choice is E, which equals to 8 and not $$\frac{60}{7}$$
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Re: Machine A can process 6000 envelopes in 3 hours. Machines B   [#permalink] 24 Dec 2015, 15:54
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