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HI
I have a basic doubt , which deals with concept
Previously , I have learnt that a line that has rising slope when moving from - ve X to + ve X will have +ve slope.
But I found in the original post of BUNNUEL that a line with - ve slope will always be in 2nd or 4th quadrant. I feel that these two statements are contradictory. We can have a line with + ve slope even if it is in 2nd quadrant. Than how can we come to conclusion that whenever we encounter a slope with - ve sign , thn it must either lie in 2nd or lie in 4 th quadrant. As we can have lines in 1st quadrant with - ve slope also........
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So for a question where it is given that slope is -1/6, Than how can be sure that line intersects 2nd quad, I found this question on GMAT prep......
in-the-rectangular-coordinate-system-shown-above-does-the-90635.html

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HI Bunuel,
As karishma has also mentioned that a line with -ve slope can also be present in 1st quadrant than how can we be so sure that it is intersecting in 2nd quadrant,

Moreover as per the theory it must intersect in 2nd and 4th quadrant ...than as per statement 1 there are two possibilities.....line intersecting in in quad 2 and 4.....But we must have only one answer form the statement, for it to be correct answer..................

Archit
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Archit143
So for a question where it is given that slope is -1/6, Than how can be sure that line intersects 2nd quad, I found this question on GMAT prep......
in-the-rectangular-coordinate-system-shown-above-does-the-90635.html

Archit

Since the slope is negative, the line will intersect the 2nd and 4th quadrant. We are talking about a line, not a line segment. A line extends indefinitely on both ends. The top end of the line will extend to intersect the 2nd quadrant under all circumstances.

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Karishma, thats what i wanted to ask....In question it asks about whether the line is intersecting 2nd quadrant....Answer is Yes it does, but at the same time it may lie in 1st quadrant also as explained by you....I think i am badly confused on this....

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Archit143
Karishma, thats what i wanted to ask....In question it asks about whether the line is intersecting 2nd quadrant....Answer is Yes it does, but at the same time it may lie in 1st quadrant also as explained by you....I think i am badly confused on this....

Archit

Does it matter whether the line also lies in other quadrants? We know that it goes through the II and IV quadrants, it may also (simultaneously) go through either I or III quadrant, but this does not alter the fact that the line goes through the II, is it? So, the answer is YES.
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Can you please explain here;


To answer, we must find the slope of each line and then check to see if one slope is the negative reciprocal of the other or if their product equals to -1.
SlopeAB=5−199−48=−14−39=0.358SlopeAB=5−199−48=−14−39=0.358

SlopeCD=24−422−31=20−9=−2.22

The formula of the slope of two given coordinates are y2-y1 / x2-x1

However in some questions, 2nd coordinates (x2 y2)s are subtracted from 1sts (x1 y1) and in some, other way around. Can you please clarify what do we take into account concerning this formula?
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mesutthefail
Can you please explain here;


To answer, we must find the slope of each line and then check to see if one slope is the negative reciprocal of the other or if their product equals to -1.
SlopeAB=5−199−48=−14−39=0.358SlopeAB=5−199−48=−14−39=0.358

SlopeCD=24−422−31=20−9=−2.22

The formula of the slope of two given coordinates are y2-y1 / x2-x1

However in some questions, 2nd coordinates (x2 y2)s are subtracted from 1sts (x1 y1) and in some, other way around. Can you please clarify what do we take into account concerning this formula?

They are both the same.

\(Slope = \frac{(y2 - y1)}{(x2 - x1)} = \frac{(y1 - y2)}{(x1 - x2)}\)

Take an example:
(x1, y1) = (2, 3)
(x2, y2) = (5, -10)

\(Slope = \frac{(y2 - y1)}{(x2 - x1)} = \frac{-10 - 3}{5 - 2} = -\frac{13}{3}\)

\(Slope = \frac{(y1 - y2)}{(x1 - x2)} = \frac{3- (-10)}{2 - 5} = -\frac{13}{3}\)
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Hello Bunuel,

Thanks a lot for the article. I have one doubt . Is it that a line with negative slope would definitely pass through Quadrant 2 and 4, and would pass through 1 or 3 depending on the value of x and y intersects?
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Hello Bunuel,

Thanks a lot for the article. I have one doubt . Is it that a line with negative slope would definitely pass through Quadrant 2 and 4, and would pass through 1 or 3 depending on the value of x and y intersects?

Yes. If the slope of a line is negative, the line WILL intersect quadrants II and IV. X and Y intersects of the line with negative slope have the same sign. Therefore if X and Y intersects are positive, the line intersects quadrant I; if negative, quadrant III.
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Hi Bunuel,

Under heading Line equation in Co-ordinate Geometry -

The equation of a straight line passing through points P1(x1,y1)P1(x1,y1) and P2(x2,y2)P2(x2,y2) is:

\(\frac{y−y1}{x−x1}=\frac{y1−y2}{x1−x2}\)

I think it should be :

\(\frac{y−y1}{x−x1}=\frac{y2−y1}{x2−x1}\)

This is because slope for two points is : \(\frac{y2-y1}{x2-x1}\)

Let me know if I am missing anything here.
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Bunuel


4. Intercept form.
The equation of a straight line whose x and y intercepts are a and b, respectively, is:
\(\frac{x}{a}+\frac{y}{b}=1\)

Example #3
Q: Find the equation of a line whose x intercept is 5 and y intercept is 2.
Solution: Substituting the values in equation \(\frac{x}{a}+\frac{y}{b}=1\) we'll get \(\frac{x}{5}+\frac{y}{2}=1\) --> \(5y+2x-10=0\) OR if we want to write the equation in the slope-intercept form: \(y=-\frac{2}{5}x+2\)



I can't figure out how you got the -10 in this 5y+2x-10=0 from \(\frac{x}{5}+\frac{y}{2}=1\)
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aalekhoza
Dear Bunuel,
Thanks for the wonderful explanation of coordinate geometry. The math guide is a surely a saviour.
I just wanted to bring your attention to the below quote, which is mentioned in the book.

Quote:
A horizontal line has a slope of zero.
The equation of a horizontal line is:
y=b
Where: x is the coordinate of any point on the line; b is where the line crosses the y-axis (y intercept). Notice that the equation is independent of x. Any point on the horizontal line satisfies the equation.

I think the highlighted text in red should be y instead of x.

Thanks :)
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Fixed that. Thank you.
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a12bansal
Hi Bunuel,

I could not dare to do this or I should not doubt the superpower of you but to clear my doubt I have to do this :D

In Slope Quadrant section :

I guess in 1st and 2nd point instead of "X and Y intersects of the line" It should be "X and Y intercepts of the line " .

Please clarify my doubt.

Thanks

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Fixed that. Thank you.
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Quote:
Example #2
Q: Find the equation of a line passing through the point A (14,23) and the slope 2.
Solution: Substituting the values in equation y−y1=m(x−x1) we'll get y−23=2(x−14) --> y=2x−5

In this question, if we have to find the other points through which the line passes how do we do that? Bunuel
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Quote:
Example #2
Q: Find the equation of a line passing through the point A (14,23) and the slope 2.
Solution: Substituting the values in equation y−y1=m(x−x1) we'll get y−23=2(x−14) --> y=2x−5

In this question, if we have to find the other points through which the line passes how do we do that? Bunuel

Any point (x,y) satisfying y = 2x − 5 is on the line y = 2x − 5.
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Bunuel
Archit143
HI Bunuel,
As karishma has also mentioned that a line with -ve slope can also be present in 1st quadrant than how can we be so sure that it is intersecting in 2nd quadrant,

Moreover as per the theory it must intersect in 2nd and 4th quadrant ...than as per statement 1 there are two possibilities.....line intersecting in in quad 2 and 4.....But we must have only one answer form the statement, for it to be correct answer..................

Archit

No, that's not what she said.

If the slope of a line is negative, line WILL intersect quadrants II and IV in ANY case. If X and Y intersects are positives, line ALSO intersects the quadrant I, if negative line ALSO intersects the quadrant quadrant III.

Bunuel
please explain me what does it means to say X and Y intersects are positive the it will intersects the quadrant I.
i didn't get what does it meant?

can you explain with example
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