Pkit
Bunuel,
you may add this to your post.
How many diagonals has a polygon with 25 sides?
the formula is:
Number of diagonals in a given polygon is =\(\frac{n*(n-3)}{2}\), where n – is the number of sides.
simple example in a square number of diagonals is =\(\frac{4*(4-3)}{2}=2\)
The below is the concept used to derive the above formula for Number of diagonals .
As we know, to make a diagonal (a line), we need 2 (a pair of) points.
if i have n sided plygon, i need to select different par of points.
This can be doen in \(nc2\) ways
but thease pairs include all the sides also. hence subtract the number of sides (\(n\)), whiich are not diagonals, from the above
==> \(The Number of diagonals\) is
==> \(nc2-n\)
==> \(\frac{n(n-1)}{2} - n\)
==> \(\frac{(n^2-3n)}{2}\)
==> \(\frac{n(n-3)}{2}\)
Regards,
Murali.
Kudos?