Mar 27 03:00 PM PDT  04:00 PM PDT Join a free live webinar and learn the winning strategy for a 700+ score on GMAT & the perfect application. Save your spot today! Wednesday, March 27th at 3 pm PST Mar 29 06:00 PM PDT  07:00 PM PDT Join a FREE 1day workshop and learn how to ace the GMAT while keeping your fulltime job. Limited for the first 99 registrants. Mar 29 10:00 PM PDT  11:00 PM PDT Right now, their GMAT prep, GRE prep, and MBA admissions consulting services are up to $1,100 off. GMAT (Save up to $261): SPRINGEXTRAGMAT GRE Prep (Save up to $149): SPRINGEXTRAGRE MBA (Save up to $1,240): SPRINGEXTRAMBA Mar 30 07:00 AM PDT  09:00 AM PDT Attend this webinar and master GMAT SC in 10 days by learning how meaning and logic can help you tackle 700+ level SC questions with ease. Mar 31 07:00 AM PDT  09:00 AM PDT Attend this webinar to learn a structured approach to solve 700+ Number Properties question in less than 2 minutes.
Author 
Message 
Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
20 Aug 2017, 19:13
There are 40 people, 28 invested in A, 16 invested in B, and 18 invested in C. Among 10 of the people who invested in both A and C, 3 also invested in B. All people who invested in B also invested in A. How many people did not invest in any of the three investments? A. 2 B. 3 C. 4 D. 5 E. 6 Attachment:
8.21.png [ 15.32 KiB  Viewed 622 times ]
Ans: C
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
20 Aug 2017, 19:15
In a certain conference, if all the n attendees shake hands 105 times, what is the value of n? A. 10 B. 12 C. 15 D. 16 E. 18 => nC 2 = 105. n(n1)/(1*2) = 105 n(n1) = 210 n(n1) = 15*14 Thus n = 15. Ans: C
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
23 Aug 2017, 01:22
If x7=√x+√7 , x=? A. 8+2√7 B. 82√7 C. 8+√7 D. 8√7 E. 7+2√8 => x7=√x+√7 (√x+√7 )(√x√7)=√x+√7 √x√7=1 √x = 1 +√7 x = (1 +√7)2 = 8 +2√7 Ans: A
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
24 Aug 2017, 01:31
If 11!/(11r)!<1,000, what is the greatest possible value of r? A. 1 B. 2 C. 3 D. 4 E. 5 => 11! / (11r)! = 11*(111)*…*(11r+1) r = 1 : 11 < 1,000 r = 2 : 11*10 = 110 < 1,000 r = 3 : 11*10*9 = 990 < 1,000 r = 4 : 11*10*9*8 = 7290 > 1,000 r = 3 Ans: C
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
25 Aug 2017, 01:14
Which of the following is the closest to 11*10^{20}–9*10^{10}? A. 10^2 B. 10^7 C. 10^{10} D. 10^{20} E. 10^{21} =>9*10^{10} is a relatively small number compared with 11*10^{20}. 11*10^{20}–9*10^{10} is approximate to 11*10^{20}, which is similar to 10^{21}. Ans: E
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
27 Aug 2017, 19:11
Which of the following inequalities is equal to x3x<8? A. 0<x<4 B. 0<x<2 C. 2<x<4 D. 2<x<2 E. 2<x<0 => 8 < x3x <8 1) x >= 0 8 < x3x < 8 8 < 2x < 8 4 < x < 4 0 <= x < 4 2) x < 0 8 < x3x < 8 8 < x+3x < 8 8 < 4x < 8 2 < x < 2 2 < x < 0 Thus, 2 < x < 4 Ans: C
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
30 Aug 2017, 01:27
If 3^x>10, which of the following must be true? I. x>2 II. x>3 III. x>4 A. I only B. II only C. III only D. I and II only E. I, II, and III => 3^x > 10 > 3^2 Thus x > 2 Ans: A
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
31 Aug 2017, 01:25
If x7=√x+√7, x=? A. 8+2√7 B. 82√7 C. 8+√7 D. 8√7 E. 7+2√6 =>x7=√x+√7 (√x+√7)(√x√7)=√x+√7 √x√7 = 1 √x = √7 + 1 x = (√7 + 1)^2 x = 7 + 2√7 + 1 = 8 + 2√7 Ans: A
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
01 Sep 2017, 10:06
(1/11)+(1/12)+……+(1/19)+(1/20) is including in which of the following ranges? A. 0 ~ (1/5) B. (1/5) ~ (1/4) C. (1/4)~(1/3) D. (1/3)~(1/2) E. (1/2)~1 => (1/20) < (1/11), (1/20) < (1/12), …, (1/20) < (1/19). (1/20) + (1/20) + … + (1/20) < (1/11)+(1/12)+……+(1/19)+(1/20) (1/20)*10 < (1/11)+(1/12)+……+(1/19)+(1/20) (1/2) < (1/11)+(1/12)+……+(1/19)+(1/20) (1/11) < (1/10), (1/12) < (1/10), … , (1/20) < (1/10) (1/11)+(1/12)+……+(1/19)+(1/20) < (1/10) + (1/10) + … + (1/10) = 1 Thus, 1/2 < (1/11)+(1/12)+……+(1/19)+(1/20) < 1 Ans: E
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
03 Sep 2017, 18:43
If n is the sum of the first 40 positive integers, what is the greatest prime factor of n? A. 29 B. 31 C. 37 D. 41 E. 43 => 1 + 2 + … + 40 = (40*41)/2 = 2^3*5*41 Thus the greatest prime factor of n is 41. Ans: D
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
03 Sep 2017, 18:45
Which of the following is the closest to 11*1010–4*104? A. 10^2 B. 10^7 C. 10^8 D. 10^9 E. 10^11 => 4*10^4 is relative small compared with 11*10^10. Thus we can consider 11*10^10 only. It is close 10^11. Ans: E
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
06 Sep 2017, 01:34
[GMAT math practice question] What is the unit digit of 3^5+4^5+5^5+6^5? A. 5 B. 6 C. 7 D. 8 E. 9 => 3^1 has a unit digit 3. 3^2 has a unit digit 9. 3^3 has a unit digit 7. 3^4 has a unit digit 1. 3^5 has a unit digit 3. 4^1 has a unit digit 4. 4^2 has a unit digit 6. 4^3 has a unit digit 4. 4^4 has a unit digit 6. 4^5 has a unit digit 4. 5^1 has a unit digit 5. 5^2 has a unit digit 5. 5^n has a unit digit 5 for all positive integers n. 6^1 has a unit digit 6. 6^2 has a unit digit 6. 6^n has a unit digit 6 for positive integers n. Thus 3 + 4 + 5 + 6 = 18 has the unit digit 8. Ans: D
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
07 Sep 2017, 01:49
[GMAT math practice question] If 3^x3^{x2}=648, x=? A. 5 B. 6 C. 7 D. 8 E. 9 => 3^x3^{x2} = 3^{x2}3^23^{x2} = 3^{x2}(3^21) = 3^{x2} x 8 = 648 3^{x2} = 81 = 3^4 x – 2 = 4 x = 6 Ans: B
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
08 Sep 2017, 01:04
[GMAT math practice question] There are 100 black balls, 100 red balls and 100 green balls evenly mixed in a jar. What is the minimum number of balls to ensure that at least 15 beans selected are the same color? A. 40 B. 41 C. 42 D. 43 E. 44 => We can assume we have 14 black balls, 14 red balls and 14 green balls. After that, if we have just one more ball, it ensures we have 15 balls with a same color. Thus we need 43 ( = (151) + (151) + (151) + 1 = 14 + 14 + 14 + 1 ) balls.40 balls ensure there are 15 balls that have a same color. Ans: D
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
10 Sep 2017, 18:24
If the gross profit of a certain company is 20 percent of the revenue from sales of the company, what percent of the cost is the gross profit? A. 20% B. 25% C. 30% D. 35% E. 40% => Let R be the revenue of the company. The profit is 0.2*R and the cost is 0.8*R. The answer is (0.2*R) / (0.8*R) * 100 = 0.25 * 100 = 25(%). Ans: B
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
10 Sep 2017, 18:26
[GMAT math practice question] (7^3)a+(7^2)b+7c+d=1045, where a, b, c, and d are integers from 0 to 6, inclusively, b=? A. 0 B. 1 C. 2 D. 3 E. 4 => 1045 = 7*149+2 = 7*(7*21 + 2) +2 = 7*(7*(7*3+0) + 2) + 2 = 7*((7^2)*3 +(7^1)*0 + 2) + 2 = (7^3)*3 +(72)*0 + (7^1)*2 + 2 Thus we have b = 0. Ans: A
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
13 Sep 2017, 00:17
[GMAT math practice question] I. 9/10, 10/11, 11/12, 12/13, 13/14 II. 10/9, 11/10, 12/11, 13/12, 14/13 III. 6/10, 7/10, 8/10, 9/10, 10/10 For which of the following options is the average (arithmetic mean) of the numbers less than the median of numbers? A. I. only B. II. only C. III. only D. II and III E. I, II and III => I. Differences between consecutive terms are 10/11 – 9/10 = 1/110, 11/12 – 10/11 = 1/132, 12/13 – 11/12 = 1/156, 13/14 – 12/13 = 1/182. The differences are getting smaller. The average is smaller than the median. II. Difference between consecutive terms are 11/10 – 10/9 = 1/90, 12/11 – 11/10 = 1/110, 13/12 – 12/11 = 1/132, 14/13 – 13/12 = 1/156. The differences are getting bigger. The average is bigger than the media. II Difference between consecutive terms are 7/10 – 6/10 = 1/10, 8/10 – 7/10 = 1/10, 9/10 – 8/10 = 1/10, 10/10 – 9/10 = 1/10. All differences are equal. The average is equal to the median. Ans: A
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
14 Sep 2017, 00:55
[GMAT math practice question] If x5=√x+√5 , x=? A. 6+2√5 B. 62√5 C. 6+√5 D. 6√5 E. 5+2√6 => x5=√x+√5 (√x+√5)(√x√5)=√x+√5 √x√5 = 1 √x = 1+√5 x = 1 + 2√5 + 5 = 6 + 2√5 Ans: A
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
15 Sep 2017, 02:03
Which of the following options is closest to (3^{10})(33^{10})? A. 10^{10} B. 10^{14} C. 10^{18} D. 10^{20} E. 10^{22} => (3^{10})(33^{10}) = (3^{10})(3*11)^{10} = (3^{10})(3^{10})(11^{10})= (9^{10})(11^{10}) ~ (10^{10})(10^{10}) = 10^{20} Ans: D
_________________



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 7115
GPA: 3.82

Re: Math Revolution Approach (PS)
[#permalink]
Show Tags
17 Sep 2017, 18:45
3 girls and 4 boys line up in a row. If girls stand at the first and boys stand at the last, how many possible cases are there? A. 96 B. 108 C. 144 D. 192 E. 256 => The number of ways that 3 girls permute is 3! = 6 and the number of ways that 4 boys permute is 4! = 24. Those cases happen together and so the number of cases that 3 girls stand at the first and 4 boys stand at the last is 3! * 4! = 6 * 24 = 144. Ans: C
_________________




Re: Math Revolution Approach (PS)
[#permalink]
17 Sep 2017, 18:45



Go to page
Previous
1 ... 12 13 14 15 16 17 18 ... 29
Next
[ 568 posts ]



