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If set A={a,b,c,d,e}, what is the number of subsets that must include only 3 elements?

A. 8
B. 10
C. 12
D. 15
E. 18

==> You get 5C3=5C2=(5)(4)/2!=10.

The answer is b.
Answer: B
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When 2 dices are tossed, what is the probability that the 2 faced numbers have a difference of 3?

A.1/9
B. 2/9
C. 1/3
D. 4/9
E. 1/6

==> Numerator:(6,3), (5,2), (4,1), (3,6), (2,5), (1,4). Denominator:6*6. Thus, you get 6/6*6=1/6.

The answer is E.
Answer: E
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If f(2x+3)=-6x, f(5)=?

A. -6
B. -3
C. -2
D. 3
E. 6

==> From2x+3=5, you get x=1, and then you get f(5)=-6(1)=-6.

The answer is A.
Answer: A
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If x=2y=4z for positive integers x, y, and z, which of the following can be the average (arithmetic mean) of x, y and 3z?

A. 15
B. 20
C. 25
D. 40
E. 47

==> You get x=4z and y=2z, and the average=(x+y+3z)/3=(4z+2z+3z)/3=3z, so it always needs to be the multiple of 3.

Therefore, the answer is A.
Answer: A
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If $10,000 is invested at 8 percent annual interest, compounded semiannually, what is the balance after 5 year, in terms of dollars?

A. 10,000(1+ )^10
B. 10,000(1+0.08)^5
C. 10,000(1+0.08)
D. 10,000(1-0.08)^2
E. 10,000*1.08

==> if it is invested at 8 percent annual interest and is compounded semiannually, From
10,000(1+8%(1/2))^2*5= 10,000(1+)^10 the answer is A

Answer: A
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3^11+3^12+3^13=?

A. 13(3^11)
B. 17(3^11)
C. 19(3^11)
D. 13(3^10)
E. 3^36

==> 3^11+3^12+3^13=(1+3+3^2)3^11=13(3^11)
Answer: A
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3 robots can finish the same task in 6hrs, 7hrs, and 8hrs.What is the greatest part of the task that can be finished by two of these robots together in 1 hour?

A. 13/42
B. 11/42
C. 42/13
D. 42/11
E. 13/21

==> Assuming that A, B, and C finishes their tasks in 6hrs, 7hrs, and 8 hrs each, the work rate of A and B are good, and each finished 1/6 and 1/7,
so you get 1/6+1/7=13/42.

The answer is A.
Answer: A
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√m^4=64 and m>0, what is the value of cubic root of m?

A. 1
B. 2
C. 4
D. 8
E. 16

==> You get √m^4=64=2^6, m^4=(2^6)^2=2^12. Then, you get m=(2^12)^1/4=2^3, and from 3√m=3√2^3=2, the answer is B.

Answer: B
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What is the units digit of 248^20?

A. 0
B. 2
C. 4
D. 6
E. 8

==>You get ~8^1=~8, ~8^2=~4, ~8^3=~2, ~8^4=~6, so the units digit becomes 8-->4-->2-->6-->8, and the index has a period of 4.
Thus, you get 248^20=(248^4)^5=(~6)^5=~6.

The answer is D.
Answer: D
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If 10!/(10-r)!<1,000, what is the greatest possible value of r?

A. 1
B. 2
C. 3
D. 4
E. 5

==>If you substitute r=1, 2, 3, 4.., for r=4, you get 10!/(10-4)!=10*9*8*7=5,040>1,000, and for r=3, you get 10!/(10-3)!=10*9*8=720<1,00.

Thus, the greatest possible value of r is r=3. The answer is C.
Answer: C
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Attachment:
7.11.png
7.11.png [ 4.08 KiB | Viewed 1808 times ]

A smaller circle is inscribed in a larger circle shown as above figure. If the smaller circle passes through the center of the larger circle, what is the ratio of the area of the region shaded to the area of the larger circle?

A. 1/2
B. 2/3
C. 3/4
D. 4/5
E. 5/6

==> Square of the ratio of the length=ratio of the area. The diameter of the smaller circle is equal to the radius of the larger circle, so the ratio of the length becomes 1:2. Then, the ratio of the area becomes 1^2:2^2=1:4. Thus, if the area of the smaller circle=k, the area of the larger circle=4k. Therefore, the area of the region shaded:the area of the larger circle=(4k-k):4k=3:4=¾.

The answer is C.
Answer: C
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If x-2=√x+√2 , x=?

A. 3+2√2
B. 3-2√2
C. 3+√2
D. 3-√2
E. 2+2√3

==> You get x-2=√x+√2 , (√x-√2)(√x+√2)= √x+√2. If you divide √x+√2 on both sides, you get √x-√2=1, then √x=√2+1. Then, if you square both sides, you get x=(√2+1)^2=2+1+2√2 =3+2√2.

The answer is A.
Answer: A
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An alarm of a certain clock rings every 15 minutes. If the clock’s alarm rings first at 12:00, when will the 15th alarm ring?

A. 14:30
B. 14:00
C. 14:30
D. 15:00
E. 15:30

==> Since the alarm rings every 15 minutes, it rings 4 times in an hour. Thus, the 15th alarm rings after 3 hours plus 3 times. Since 13th alarm is at 15:00, 15th alarm rings at 15:30.

Therefore, the answer is E.
Answer: E
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If x>0, y<0, and a>b>0, then which of the following is (are) positive?
Ⅰ. ax+by Ⅱ. ax-by Ⅲ. by-ax

A. Ⅰonly
B. Ⅱ only
C. Ⅲ only
D.Ⅰ& Ⅱ only
E. Ⅱ & Ⅲ only


==> You getⅠ. ax+by a=2, b=x=1, y=-10, which is negative. (X)
From Ⅱ. ax-by by<0, you get –by>0 and ax>0, ax-by>0, hence it is always positive. (O)
From Ⅲ. by-ax a=2, b=1, x=1, y=-10, it is negative. (X)

Therefore, the answer is B.
Answer: B
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For a positive integer x, the units digits of (x+2)^2 and (x+6)^2 are 9. What is the units digit of (x+3)^2?

A. 0
B. 2
C. 4
D. 6
E. 8

==>It needs to satisfy x=~1. Thus, you get ~3^2=~9 and ~7^2=~9. If you substitute X=~1, you get (x+3)^2=~4^2=~6.

The answer is D.
Answer: D
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If the sum of all the even numbers from 1 to n(n: odd number) is 69*70, what is the value of n?

A. 135
B. 137
C. 139
D. 141
E. 143

==> If n=2m+1, the even numbers until 2m+1 becomes until 2m, and the sum of the even numbers is 2+4+…+2m=2(1+2+…m)=2m(m+1)/2=m(m+1). From m(m+1)=69*70, you get m=69, which becomes 2m+1=2(69)+1=139.

The answer is C.
Answer: C
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When 8^101-8 is divided by 10, what is the remainder?

A. 0
B. 1
C. 2
D. 3
E. 4

==> You get 8^101-8=8(8^100-1), and the units digit of ~8 becomes ~8^1=~8, ~8^2=~4, ~8^3=~2, ~8^4=~6. You get 8(8^100-1)=8{(8^4)^25-1}=8{(~6^25)-1}=8(~6-1)=8(~5)=~0, and the answer is A.

Answer: A
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