Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
If p is the sum of all odd numbers greater than 0 but less than 50, and q is the sum of all even numbers greater than 0 but less than 50, what is the value of p-q?
A. -24 B. 0 C. 1 D. 24 E. 25
==> Since p=1+3+….+47+49, from q=2+4+…+46+48, the difference between 3+5+…+47+49 (part of p) and q=2+4+..+46+48 is 1 each, so there are 24. Since there is also +1 at the front of p, you get 24+1=25.
3 robots can finish the same task in 6hrs, 7hrs, and 8hrs.What is the greatest part of the task that can be finished by two of these robots together in 1 hour?
A. 13/42 B. 11/42 C. 42/13 D. 42/11 E. 13/21
==> Assuming that A, B, and C finishes their tasks in 6hrs, 7hrs, and 8 hrs each, the work rate of A and B are good, and each finished 1/6 and 1/7, so you get 1/6+1/7=13/42.
==>You get ~8^1=~8, ~8^2=~4, ~8^3=~2, ~8^4=~6, so the units digit becomes 8-->4-->2-->6-->8, and the index has a period of 4. Thus, you get 248^20=(248^4)^5=(~6)^5=~6.
A smaller circle is inscribed in a larger circle shown as above figure. If the smaller circle passes through the center of the larger circle, what is the ratio of the area of the region shaded to the area of the larger circle?
A. 1/2 B. 2/3 C. 3/4 D. 4/5 E. 5/6
==> Square of the ratio of the length=ratio of the area. The diameter of the smaller circle is equal to the radius of the larger circle, so the ratio of the length becomes 1:2. Then, the ratio of the area becomes 1^2:2^2=1:4. Thus, if the area of the smaller circle=k, the area of the larger circle=4k. Therefore, the area of the region shaded:the area of the larger circle=(4k-k):4k=3:4=¾.
==> You get x-2=√x+√2 , (√x-√2)(√x+√2)= √x+√2. If you divide √x+√2 on both sides, you get √x-√2=1, then √x=√2+1. Then, if you square both sides, you get x=(√2+1)^2=2+1+2√2 =3+2√2.
An alarm of a certain clock rings every 15 minutes. If the clock’s alarm rings first at 12:00, when will the 15th alarm ring?
A. 14:30 B. 14:00 C. 14:30 D. 15:00 E. 15:30
==> Since the alarm rings every 15 minutes, it rings 4 times in an hour. Thus, the 15th alarm rings after 3 hours plus 3 times. Since 13th alarm is at 15:00, 15th alarm rings at 15:30.
If x>0, y<0, and a>b>0, then which of the following is (are) positive? Ⅰ. ax+by Ⅱ. ax-by Ⅲ. by-ax
A. Ⅰonly B. Ⅱ only C. Ⅲ only D.Ⅰ& Ⅱ only E. Ⅱ & Ⅲ only
==> You getⅠ. ax+by a=2, b=x=1, y=-10, which is negative. (X) From Ⅱ. ax-by by<0, you get –by>0 and ax>0, ax-by>0, hence it is always positive. (O) From Ⅲ. by-ax a=2, b=1, x=1, y=-10, it is negative. (X)
If the sum of all the even numbers from 1 to n(n: odd number) is 69*70, what is the value of n?
A. 135 B. 137 C. 139 D. 141 E. 143
==> If n=2m+1, the even numbers until 2m+1 becomes until 2m, and the sum of the even numbers is 2+4+…+2m=2(1+2+…m)=2m(m+1)/2=m(m+1). From m(m+1)=69*70, you get m=69, which becomes 2m+1=2(69)+1=139.
When 8^101-8 is divided by 10, what is the remainder?
A. 0 B. 1 C. 2 D. 3 E. 4
==> You get 8^101-8=8(8^100-1), and the units digit of ~8 becomes ~8^1=~8, ~8^2=~4, ~8^3=~2, ~8^4=~6. You get 8(8^100-1)=8{(8^4)^25-1}=8{(~6^25)-1}=8(~6-1)=8(~5)=~0, and the answer is A.