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ismail207
B----210 miles----A
speed of A (sA)= 48 mi/h
speed of B (sB)= 65 mi/h
* A leaves at 3 PM, and B leaves at 5 PM, so A has a head start of 2 hours
At what time will the Car B overtake Car A?
In other words we are interested on how long it takes for B to reach A (after 5 PM), B----0----A
* We can already calculate the distance between A and B at 5 PM,
since A has been moving east for 2 hours, B--distance (d)--A at 5 PM,
d = 210(mi) + 48(mi/h) * 2(h) = 306 miles
Now we can calculate the time it takes for B to reach A, that is t = d / (sB - sA)
t = 306 / (65 - 48) = 18 hours
So at what time B reaches A is 5 PM + 18 hours, convert it clock wise, that is at 11 AM
The answer is C
