ismail207
Town A lies 210 miles due east of Town B along a road. Car A leaves Town A at 3:00pm and travels east at rate of 48 miles per hour. Car B leaves Town B at 5:00pm on the same day and travels east along an adjacent road at a rate of 65 miles per hour. At what time will the Car B overtake Car A?
(A) 12pm
(B) 11pm
(C) 11am
(D) 10pm
(E) 12am
Can someone help with this question?
B----210 miles----A
speed of A (sA)= 48 mi/h
speed of B (sB)= 65 mi/h
* A leaves at 3 PM, and B leaves at 5 PM, so A has a head start of 2 hours
At what time will the Car B overtake Car A?
In other words we are interested on how long it takes for B to reach A (after 5 PM), B----0----A
* We can already calculate the distance between A and B at 5 PM,
since A has been moving east for 2 hours, B--distance (d)--A at 5 PM,
d = 210(mi) + 48(mi/h) * 2(h) = 306 miles
Now we can calculate the time it takes for B to reach A, that is t = d / (sB - sA)
t = 306 / (65 - 48) = 18 hours
So at what time B reaches A is 5 PM + 18 hours, convert it clock wise, that is at 11 AM
The answer is C