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27 Jan 2021, 14:06
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D
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Difficulty:
25%
(medium)
Question Stats:
79% (02:04) correct
21%
(02:45)
wrong
based on 226
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Nine cards numbered from 1 to 9 are placed in an empty bowl. Four cards are drawn from the bowl one-by-one without replacement to form a four-digit number (first card gives the thousands digit, second card gives the hundreds digit, third card gives the tens digit and fourth card gives the units digit). What it the probability that the four-digit number is even?
A. 1/9
B. 2/9
C. 3/9
D. 4/9
E. 5/9
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
M37-64
A. 1/9
B. 2/9
C. 3/9
D. 4/9
E. 5/9
Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
M37-64
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30 Nov 2021, 03:55
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Official Solution:
Nine cards numbered from 1 to 9 are placed in an empty bowl. Four cards are drawn from the bowl one-by-one without replacement to form a four-digit number (first card gives the thousands digit, second card gives the hundreds digit, third card gives the tens digit and fourth card gives the units digit). What it the probability that the four-digit number is even?
A. \(\frac{1}{9}\)
B. \(\frac{2}{9}\)
C. \(\frac{3}{9}\)
D. \(\frac{4}{9}\)
E. \(\frac{5}{9}\)
The four-digit number will be even if the units digit is even. So, the question basically asks about the probability that 4th card picked will be even. There are 4 even cards from 9, so the probability that 4th card will be even is \(\frac{4}{9}\).
To elaborate more: the initial probability of drawing an even card is \(\frac{4}{9}\). Without knowing the other results, the probability of drawing an even card will not change for ANY successive drawing: second, third, fourth... There is simply no reason to believe WHY is any drawing different from another (provided we don't know the other results).
Answer: D
Nine cards numbered from 1 to 9 are placed in an empty bowl. Four cards are drawn from the bowl one-by-one without replacement to form a four-digit number (first card gives the thousands digit, second card gives the hundreds digit, third card gives the tens digit and fourth card gives the units digit). What it the probability that the four-digit number is even?
A. \(\frac{1}{9}\)
B. \(\frac{2}{9}\)
C. \(\frac{3}{9}\)
D. \(\frac{4}{9}\)
E. \(\frac{5}{9}\)
The four-digit number will be even if the units digit is even. So, the question basically asks about the probability that 4th card picked will be even. There are 4 even cards from 9, so the probability that 4th card will be even is \(\frac{4}{9}\).
To elaborate more: the initial probability of drawing an even card is \(\frac{4}{9}\). Without knowing the other results, the probability of drawing an even card will not change for ANY successive drawing: second, third, fourth... There is simply no reason to believe WHY is any drawing different from another (provided we don't know the other results).
Answer: D
General Discussion
27 Jan 2021, 14:30
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Bunuel
Nine cards numbered from 1 to 9 are placed in an empty bowl. Four cards are drawn from the bowl one-by-one without replacement to form a four-digit number (first card gives the thousands digit, second card gives the hundreds digit, third card gives the tens digit and fourth card gives the units digit). What it the probability that the four-digit number is even?
A. 1/9
B. 2/9
C. 3/9
D. 4/9
E. 5/9
A. 1/9
B. 2/9
C. 3/9
D. 4/9
E. 5/9
In order for the four-digit number to be even, the last (4th) digit must be even
P(4th the digit is even) = P(3rd the digit is even) = P(2nd the digit is even) = P(1st the digit is even) = 4/9 (since 4 of the nine digits are even)
Answer: D
