Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs.

Question

Competition Mode Question

Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs. The contribution of Nishant is 3/5thof the contribution of Rakesh, Brijesh, and Rohit taken together. The contribution of Rakesh is 2/3rd of the contribution of Brijesh and Rohit taken together. Brijesh and Rohit contributed equal amount. What is the ratio of their respective contributions?

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

Are You Up For the Challenge: 700 Level Questions

freedom128 · Answer

There are N, Ra, B, Ro

* B=Ro, so B:Ro=1:1 or alike.  Thus, we can eliminate choices A, D, E  since these choices don't reflect correct ratio of B:Ro

* Ra= 2/3*(B+Ro). Let's test the remaining choices:
B. 8:4:2:2 --> Ra= 2/3*(2+2)=8/3 (No!!) 
C. 6:4:3:3 --> Ra= 2/3*(3+3)=4 (Yes!!)

The clear winner -and the final answer- is (C)

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rocksailor9 · Answer

given in the stem:

brejash, Rohit = x, x
Ra = 2(x+x)/3
N = 3(x+x+4/3x)/5
hence: N|Ra|BRAJESH|Rohit = 2x| 4/3x |x | x respectively
Ratio becomes = 6:4:3:3

exc4libur · Answer

N:R:B:H
N=3/5(R+B+H)
R=2/3(B+H)
B=H

R: 2/3(B+H)=2/3(B+B)=2/3(2B)=4B/3
N: 3/5(R+B+H)=3/5(R+2B)=3/5(4B/3+2B)=3/5(10B/3)=2B

N:R:B:H= *3=6B:4B:3B:3B=6:4:3:3

Ans (C)

Jawad001 · Answer

Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs. The contribution of Nishant is 3/5thof the contribution of Rakesh, Brijesh, and Rohit taken together. The contribution of Rakesh is 2/3rd of the contribution of Brijesh and Rohit taken together. Brijesh and Rohit contributed equal amount. What is the ratio of their respective contributions?

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

Solution:
Nishant = N, Rakesh = Ra, Brijesh = B, and Rohit = Ro
Suppose, Contribution of Brijesh = Rohit = 3x
Contribution of Rakesh = 2/3*(Brijesh + Rohit) = 2/3*(6x) = 4x
Contribution of Nishat = Contribution of (Ra + B +Ro)*3/5 = 10x*(3/5) = 6x

Ratio of contribution: N : Ra : B : Ro = 6x : 4x : 3x : 3x 
= 6 : 4 : 3 : 3(C)

unraveled · Answer

Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs. The contribution of Nishant is 3/5thof the contribution of Rakesh, Brijesh, and Rohit taken together. The contribution of Rakesh is 2/3rd of the contribution of Brijesh and Rohit taken together. Brijesh and Rohit contributed equal amount. What is the ratio of their respective contributions?

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

Only options B and C satisfy the conditions since contribution by Rohit and Brijesh are equal.
Let Ni, Ra, Br and Ro are contributions made by Nishant, Rakesh, Brijesh, and Rohit respectively.

Now,  Ni = \frac{3}{5}(Ra + Br + Ro)  and  Ra = \frac{2}{3}(Br + Ro)  where Br = Ro
 5Ni = 3(Ra + 2Ro)  and 3Ra = 4Ro

So, 5Ni = 3Ra + 6Ro
5Ni = 10Ro 
Ni = 2Ro and  Ra = \frac{4}{3}Ro

Taking everything in terms of Ro
 Ni:Ra:Br:Ro = 2Ro:\frac{4}{3}Ro:Ro:Ro = 6:4:3:3

Answer C.

draftpunk · Answer

Start from the end:

Brijesh = Rohit = x

Rakesh = (2/3) * (Brijesh + Rohit) = (2/3) * (x + x) = (2/3) * (2x) = (4/3)x

Nishant = (3/5) * (Rakesh + Brijesh + Rohit) = (3/5) * ((4/3)x + x + x) = (30/15)x = 2x

LCM of: 2x : (4/3)x : x : x = 6:4:3:3

CareerGeek · Answer

Let the contribution of B = Ro = a 
—> Ra = 2/3*(2a) = 4/3a
& N = 3/5(4/3a + a + a) = 2a

N:Ra:B:Ro = 2a : 4/3a : a : a = 6a : 4a : 3a : 3a
= 6 : 4 : 3 : 3

Option C

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effatara · Answer

Brijesh and Rohit contributed equal amounts so their ratios must be the same. This rules out options (A), (D) and (E) leaving only (B) and (C). According to (B), the ratio of Rakesh (4) is equal to the sum of the ratios of Brijesh and Rohit (2+2) but, as per the question, Brijesh's ratio must be 2/3 of the combined ratios of Brijesh and Rohit. So (B) is not the right option which leaves only (C) which satisfies all three stipulated conditions:
(a) Niten's contribution (6) is equal to 3/5 of the sum of the contributions of Rakesh, Brijesh and Rohit (3/5 of 10=6)
(b) Rakesh's contribution (4) is equal to 2/3 of the sum of the contributions of Brijesh and Rohit (2/3 of 6=4)
(c) Brijesh's (3) contribution is equal to that of Rohit (3).
ANS: C

Shivangigmat · Answer

C is the answer

Replacing 40 lakh by 100

3/5 of 100 is 60

So we know answer will have 6 first

Rohit and brijesh have equal control so 3:3 at end tells us it is the correct answer

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KalyanChamarthi · Answer

Nishant ( N ) Rakesh (R) Brijesh ( B) Rohit ( Ro)

B = Ro 
R = (2/3)(B+Ro) = (2/3) ( B + B ) = (2/3) (2B) = 4B/3 
N = (3/5) ( R+B+Ro) = (3/5) (4B/3 + B + B) = (3/5)(10B/3) = 2B

N:R:B:Ro = 2B: (4B/3):B: B = 6B:4B:3B:3B = 6:4:3:3

Ans: C.

Archit3110 · Answer

given
n+r+b+ro=4*10^6
n=3/5 * ( r+b+ro)
r=2/3*(b+ro)
b=ro
we get
8/5 * ( r+b+ro)
18/5 * ( 5/3*(b+ro)
8/3* 2B = 4*10^6
B = Ro = 75*10^4
we get R= 10^6
and N = 15*10^5
Ratio
15*10^5: 10^6: 75*10^4:75*10^4
150:100:75:75
30:20:15:15 
 6:4:3:3
IMO C

Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs. The contribution of Nishant is 3/5thof the contribution of Rakesh, Brijesh, and Rohit taken together. The contribution of Rakesh is 2/3rd of the contribution of Brijesh and Rohit taken together. Brijesh and Rohit contributed equal amount. What is the ratio of their respective contributions?

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

A. 6:4:3:1
B. 8:4:2:2
C. 6:4:3:3
D. 5:4:3:4
E. 7:4:3:4

eakabuah · Answer

Ni+Ra+Br+Ro=Rs.40 lakhs

But we are informed that: 
Ni=3/5 *(Ra+Br+Ro) -------(1)
Ra=2/3 *(Br+Ro) -------(2)
Br=Ro -------(3)
So Ra = 2/3 *(2Ro) = 4Ro/3
and Ni = 3/5 *(4Ro/3 + 6Ro/2) = 3/5 * 10Ro/3 = 2Ro
Hence Ni:Ra:Br:Ro = 2:4/3:1:1 = 6:4:3:3

The answer is C.

madgmat2019 · Answer

LET B=Ro= x THEN
Ra Becomes 4/3x, N becomes 2x

N:Ra:B:Ro = 6:4:3:3

OA:C

fauji · Answer

Approach:

- Assume contribution by Brijesh = Rohit = x(both contributed equal amount), Rakesh = y, and Nishant = z

Given : y = 2/3(x+x) and z = 3/5(y+x+x) or 3/5(2/3(2x)+2x)

- Total(z+y+x+x) = 40 => 2/3(2x) + 4/5x + 6/5x + x + x

- On Solving we get x = 7.5, y = 10, z =15

- So, ratio for values 15:10:7.5:7.5 will be 6:4:3:3

Option C!

lacktutor · Answer

N + Ra+ B + Ro = 40
 N= \frac{3}{5}(Ra+ B+ Ro) —> Ra+ B+ Ro=( \frac{5}{3})N

—>  N+( \frac{5}{3})N = 40

(\frac{8}{3})N= 40  —>  N = 15

Ra + B+Ro= 25

Ra=(\frac{ 2}{3})(B+ Ro)

—>  B+ Ro=( \frac{3}{2})Ra

Ra+ (\frac{3}{2})Ra = 25 
Ra= 10

—>  B= \frac{15}{2} ,  Ro= \frac{15}{2}

15: 10: \frac{15}{2}: \frac{15}{2}   (dividing by 3 )

—>  3: 2: \frac{3}{2}: \frac{3}{2}  (multiplying by 2)

—> 6:4:3:3

The answer is C

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Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs.

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Nishant, Rakesh, Brijesh, and Rohit bought a house for Rs.40 lakhs.

Prep Toolkit

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