January 17, 2019 January 17, 2019 08:00 AM PST 09:00 AM PST Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL. January 19, 2019 January 19, 2019 07:00 AM PST 09:00 AM PST Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.
Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 25 Oct 2005
Posts: 15

Of the 12 temporary employees in a certain company, 4 will
[#permalink]
Show Tags
16 Nov 2005, 02:01
Question Stats:
81% (00:53) correct 19% (01:24) wrong based on 654 sessions
HideShow timer Statistics
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man? A. 22 B. 35 C. 56 D. 70 E. 105
Official Answer and Stats are available only to registered users. Register/ Login.




Math Expert
Joined: 02 Sep 2009
Posts: 52231

Re: GMAT Prep: Probabilities
[#permalink]
Show Tags
27 Dec 2009, 16:54




Manager
Joined: 04 Feb 2007
Posts: 77

Re: GMAT Prep: Probabilities
[#permalink]
Show Tags
21 Feb 2010, 18:51
dk94588 wrote: This is a section I have had a lot of trouble with, and I was hoping someone could show me how to do this.
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
a) 22 b) 35 c) 56 d) 70 e) 105 The wording of this question is pure evil. First it gives you information regarding 4 permanent employees, then it asks you concerning groups of temporary employees. The information of the permanent employees is irrelevant to this problem. Make sure to understand exactly what the question is asking before attacking it.
_________________
If you like my post, a kudos is always appreciated




Director
Joined: 13 Nov 2003
Posts: 766
Location: BULGARIA

Select three women out of five in 5C3=10 ways.Select one man in 7 ways or 10x7=70 different groups of 3 women and 1 man.



VP
Joined: 06 Jun 2004
Posts: 1005
Location: CA

Re: PS: employees
[#permalink]
Show Tags
16 Nov 2005, 11:13
themagiccarpet wrote: Of the 12 temporary employees in a certain company, 4 will be hired as permanent emploees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 temporary employees consist of 3 women and 1 man?
(A)22 (B)35 (C)56 (D)70 (E)105
Possible groups = Possible groups of 3 women * possible groups of 1 men
Since order does not matter, its a combination problem.
=[5!/(3!2!)} * [7!/(6!1!)]
=70



SVP
Joined: 29 Aug 2007
Posts: 2359

Re: GMAT Prep: Probabilities
[#permalink]
Show Tags
27 Dec 2009, 12:56
dk94588 wrote: This is a section I have had a lot of trouble with, and I was hoping someone could show me how to do this.
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
a) 22 b) 35 c) 56 d) 70 e) 105 Select 3 out of 5 = 5c3 = 5 Select 1 out of 7 = 7c1 = 7 Total = 5c3 x 7c1 = 5x7 = 35
_________________
Verbal: http://gmatclub.com/forum/newtotheverbalforumpleasereadthisfirst77546.html Math: http://gmatclub.com/forum/newtothemathforumpleasereadthisfirst77764.html Gmat: http://gmatclub.com/forum/everythingyouneedtoprepareforthegmatrevised77983.html
GT



Intern
Joined: 25 Dec 2009
Posts: 46

Re: GMAT Prep: Probabilities
[#permalink]
Show Tags
27 Dec 2009, 23:02
5c3*7c1=70 but come on 75% jobs for females? where is the right to equality



Manager
Joined: 17 Aug 2009
Posts: 176

Re: GMAT Prep: Probabilities
[#permalink]
Show Tags
29 Dec 2009, 04:41
5C3 * 7C1
= [5!/(53)!* 3!] = 7!/(71)! * 1! =70
In general, the formula for nCr is n!/[(nr)!] * r!
Hope this helps



Manager
Joined: 17 Oct 2010
Posts: 75

Re: GMAT Prep: Probabilities
[#permalink]
Show Tags
08 Jun 2012, 00:10
another approach :
one scenario : [WWWM]
now we have 5 ways for the first women , 4 ways for the 2nd women and , 3 ways for the third women.
and 7 ways to select one man
so 5*4*3*7 = 420
now the three women are same so combinations with win them are irrelevant the 3 women can we arranged in 3! ways
hence 420/3!= 420/6= 70



Current Student
Joined: 03 Sep 2012
Posts: 380
Location: United States
Concentration: Healthcare, Strategy
GPA: 3.88
WE: Medicine and Health (Health Care)

Re: Of the 12 temporary employees in a certain company, 4 will
[#permalink]
Show Tags
24 Sep 2012, 06:13
Total number of Women = 5 Total Number of Men = 4 No of employers to be hired  04 No. of Women employees to be hired  03 (Given in the question) No. of Men to be hired  1 (given in the question) Therefore number of Combinations = C(5,3) x C (7,1) = 10 x 7 = 70 (D)
_________________
"When you want to succeed as bad as you want to breathe, then you’ll be successful.”  Eric Thomas



VP
Status: Been a long time guys...
Joined: 03 Feb 2011
Posts: 1111
Location: United States (NY)
Concentration: Finance, Marketing
GPA: 3.75

Re: Of the 12 temporary employees in a certain company,
[#permalink]
Show Tags
02 Jan 2013, 20:44
kiyo0610 wrote: Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 temporary employees consist of 3 women and 1 man?
(A) 22 (B) 35 (C) 56 (D) 70 (E) 105 Number of ways to select 3 women out of 5 is \(5C3\) and the number of ways to select 1 man out of 7 is \(7C1\). Therefore number of possible groups of 4 temporary employees consist of 3 women and 1 man are \(7C1 * 5C3 = 70\). There are 70 possible groups. +1D
_________________
Prepositional Phrases ClarifiedElimination of BEING Absolute Phrases Clarified Rules For Posting www.UnivScholarships.com



Intern
Joined: 02 Nov 2012
Posts: 31

Re: Of the 12 temporary employees in a certain company, 4 will
[#permalink]
Show Tags
04 Jan 2013, 04:14
I understand the question completely, however can somebody right the answer down when the order is important in both groups. I understand how to right it down with permutations like 5 P 3 and 7 P 1, however how do you right it down in faculty form?



Manager
Joined: 06 Sep 2018
Posts: 171
Location: Pakistan
Concentration: Finance, Operations
GPA: 2.87
WE: Engineering (Other)

Re: Of the 12 temporary employees in a certain company, 4 will
[#permalink]
Show Tags
27 Oct 2018, 07:12
5C3=10 7C1=7 Total combinations=10*7=70
_________________
Hitting Kudos is the best way of appreciation.
Eric Thomas, "When you want to succeed as bad as you want to breathe, then you'll be successful."



Senior Manager
Joined: 27 Dec 2016
Posts: 275

Re: Of the 12 temporary employees in a certain company, 4 will
[#permalink]
Show Tags
30 Oct 2018, 17:33
Hi Bunuel, I was wondering could you please explain where I went wrong in my approach? I got E instead of D. WWWM can be arranged in (4!/3!*1!) or 4 ways total We have 5 ways to select the first women, 4 ways for the 2nd women and, 3 ways for the third women. Similarly, we have 7 ways to select one man 5*4*3*7 = 420 420/4 = 105




Re: Of the 12 temporary employees in a certain company, 4 will &nbs
[#permalink]
30 Oct 2018, 17:33






