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Of the 12 temporary employees in a certain company, 4 will
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16 Nov 2005, 02:01
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82% (00:52) correct 18% (01:21) wrong based on 623 sessions
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Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man? A. 22 B. 35 C. 56 D. 70 E. 105
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Re: GMAT Prep: Probabilities
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27 Dec 2009, 16:54




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Re: GMAT Prep: Probabilities
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21 Feb 2010, 18:51
dk94588 wrote: This is a section I have had a lot of trouble with, and I was hoping someone could show me how to do this.
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
a) 22 b) 35 c) 56 d) 70 e) 105 The wording of this question is pure evil. First it gives you information regarding 4 permanent employees, then it asks you concerning groups of temporary employees. The information of the permanent employees is irrelevant to this problem. Make sure to understand exactly what the question is asking before attacking it.
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Select three women out of five in 5C3=10 ways.Select one man in 7 ways or 10x7=70 different groups of 3 women and 1 man.



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16 Nov 2005, 11:13
themagiccarpet wrote: Of the 12 temporary employees in a certain company, 4 will be hired as permanent emploees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 temporary employees consist of 3 women and 1 man?
(A)22 (B)35 (C)56 (D)70 (E)105
Possible groups = Possible groups of 3 women * possible groups of 1 men
Since order does not matter, its a combination problem.
=[5!/(3!2!)} * [7!/(6!1!)]
=70



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Re: GMAT Prep: Probabilities
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27 Dec 2009, 12:56
dk94588 wrote: This is a section I have had a lot of trouble with, and I was hoping someone could show me how to do this.
Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
a) 22 b) 35 c) 56 d) 70 e) 105 Select 3 out of 5 = 5c3 = 5 Select 1 out of 7 = 7c1 = 7 Total = 5c3 x 7c1 = 5x7 = 35
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Re: GMAT Prep: Probabilities
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27 Dec 2009, 23:02
5c3*7c1=70 but come on 75% jobs for females? where is the right to equality



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Re: GMAT Prep: Probabilities
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29 Dec 2009, 04:41
5C3 * 7C1
= [5!/(53)!* 3!] = 7!/(71)! * 1! =70
In general, the formula for nCr is n!/[(nr)!] * r!
Hope this helps



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Re: GMAT Prep: Probabilities
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08 Jun 2012, 00:10
another approach :
one scenario : [WWWM]
now we have 5 ways for the first women , 4 ways for the 2nd women and , 3 ways for the third women.
and 7 ways to select one man
so 5*4*3*7 = 420
now the three women are same so combinations with win them are irrelevant the 3 women can we arranged in 3! ways
hence 420/3!= 420/6= 70



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Re: Of the 12 temporary employees in a certain company, 4 will
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24 Sep 2012, 06:13
Total number of Women = 5 Total Number of Men = 4 No of employers to be hired  04 No. of Women employees to be hired  03 (Given in the question) No. of Men to be hired  1 (given in the question) Therefore number of Combinations = C(5,3) x C (7,1) = 10 x 7 = 70 (D)
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Re: Of the 12 temporary employees in a certain company,
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02 Jan 2013, 20:44
kiyo0610 wrote: Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 temporary employees consist of 3 women and 1 man?
(A) 22 (B) 35 (C) 56 (D) 70 (E) 105 Number of ways to select 3 women out of 5 is \(5C3\) and the number of ways to select 1 man out of 7 is \(7C1\). Therefore number of possible groups of 4 temporary employees consist of 3 women and 1 man are \(7C1 * 5C3 = 70\). There are 70 possible groups. +1D
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Re: Of the 12 temporary employees in a certain company, 4 will
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04 Jan 2013, 04:14
I understand the question completely, however can somebody right the answer down when the order is important in both groups. I understand how to right it down with permutations like 5 P 3 and 7 P 1, however how do you right it down in faculty form?



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Re: Of the 12 temporary employees in a certain company, 4 will
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27 Oct 2018, 07:12
5C3=10 7C1=7 Total combinations=10*7=70
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Re: Of the 12 temporary employees in a certain company, 4 will
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30 Oct 2018, 17:33
Hi Bunuel, I was wondering could you please explain where I went wrong in my approach? I got E instead of D. WWWM can be arranged in (4!/3!*1!) or 4 ways total We have 5 ways to select the first women, 4 ways for the 2nd women and, 3 ways for the third women. Similarly, we have 7 ways to select one man 5*4*3*7 = 420 420/4 = 105




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