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18 Oct 2020, 06:40
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altairahmad
Because, in WWWM you are taking arrangement of just the Ws and 7C1 is the selection of one M, so in 5*4*3*7, the arrangement is for 5*4*3, so divide it by 3!=5*4*3/3!
But you can also select M in 7 ways so multiply by 7=> 7*5*4*3/3!
18 Oct 2020, 07:41
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Given: Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees.
Asked: If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
Favorable ways = 5C3 * 7C1 = 10*7 = 70
IMO D
Asked: If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
Favorable ways = 5C3 * 7C1 = 10*7 = 70
IMO D
altairahmad
18 Oct 2020, 08:29
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chetan2u
Thanks for the reply.
Order doesn't matter for the whole WWWM arrangement right ? If we were told to find different arrangements of WWWM it would have been 4!/3! right ? Then why is in this case the arrangements just 3! ? It's as if M can't change the position.[/quote]
Because, in WWWM you are taking arrangement of just the Ws and 7C1 is the selection of one M, so in 5*4*3*7, the arrangement is for 5*4*3, so divide it by 3!=5*4*3/3!
But you can also select M in 7 ways so multiply by 7=> 7*5*4*3/3![/quote]
Thanks again for the reply.
Actually I am still not sure I understand. In what case would it have been ok to divide by 4!/3! ? Maybe by comparing the two scenarios I can get the crux of the issue.
What I have usually been doing is this : Find the number of ways WWWM can be arranged (order matters scenario) and then divide by the number of arrangements to get the unique combinations in which order does not matter i.e 4!/3!. It was working so well until now.....😭😭
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