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Of the following, which is least?

A. \(\frac{-0.7}{0.000012}\)

B. \(\frac{0.7}{-0.00012}\)

C. \(-\frac{0.7}{0.0012}\)

D. \((\frac{0.012}{-0.7})^{(-1)}\)

E. \(-\frac{0.7}{0.12}\)


A NEGATIVE sign will mean the SAME irrespective of it at numerator or denominator..
D has two NEGATIVE signs making it POSITIVE.... Eliminate.

Remaining choices are negative and with same numerator 0.7..
So let's concentrate on denominator only..

LOWER the denominator, HIGHER the value of fraction if positive and LOWER the value of fraction if NEGATIVE.

0.000012 is the lowest value making \(\frac{-0.7}{0.000012}\) the least

A

D is \((\frac{0.012}{-0.7})\) to the power of -1. Does it look like a multiplication? I'll try to edit somehow if it does.
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Of the following, which is least?

A. \(\frac{-0.7}{0.000012}\)

B. \(\frac{0.7}{-0.00012}\)

C. \(-\frac{0.7}{0.0012}\)

D. \((\frac{0.012}{-0.7})^{(-1)}\)

E. \(-\frac{0.7}{0.12}\)


A NEGATIVE sign will mean the SAME irrespective of it at numerator or denominator..
D has two NEGATIVE signs making it POSITIVE.... Eliminate.

Remaining choices are negative and with same numerator 0.7..
So let's concentrate on denominator only..

LOWER the denominator, HIGHER the value of fraction if positive and LOWER the value of fraction if NEGATIVE.

0.000012 is the lowest value making \(\frac{-0.7}{0.000012}\) the least

A

D is \((\frac{0.012}{-0.7})\) to the power of -1. Does it look like a multiplication? I'll try to edit somehow if it does.


Actually -1 is at the level of numerator and seemed to be in the same line, so misread it. Thanks
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Numerator of all choices is 0.7.
Compare denominators: 0.12>0.012>0.0012>0.00012>0.000012.
Combine: the higher denominator, the lower fraction: 0.7/0.12 < 0.7/0.012 <0.7/0.0012 <0.7/0.00012 <0.7/0.000012
Add negative sign makes largest become least. So answer is A.
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When a positive number is divided by a number between 0 and 1 the result (quotient) gets bigger, the smaller the divisor, the bigger the quotient.

When a negative number is divided by a number between 0 and 1 the result gets smaller (moves to the left on the number line), the smaller the divisor, the smaller the quotient

in A divisor is the smallest among the denominators. Therefore the result of A will be furthest to the left on the number line

hope it helps
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Bunuel
Of the following, which is least?

A. \(\frac{-0.7}{0.000012}\)

B. \(\frac{0.7}{-0.00012}\)

C. \(-\frac{0.7}{0.0012}\)

D. \((\frac{0.012}{-0.7})^{(-1)}\)

E. \(-\frac{0.7}{0.12}\)

Par of GMAT CLUB'S New Year's Quantitative Challenge Set

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First up, Looking at the options, eliminate D. This was at first glance the most problematic one. This has a different denominator making it harder. Since that is out, we can focus on the other options which also is elementary fractions.

Make all the denominators as 12.

A. -700000/12
B. -70000/12
C. -7000/12
E. -70/12

On the number line, the negative number with the largest magnitude is the least. Hence, Option A is the answer.
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A. \(\frac{-0.7}{0.000012}\) = \(\frac{-7}{12}\) * 10^5

B. \(\frac{0.7}{-0.00012}\) = \(\frac{-7}{12}\) * 10^4

C. \(-\frac{0.7}{0.0012}\) = \(\frac{-7}{12}\) * 10^3

D. \((\frac{0.012}{-0.7})^{(-1)}\) = \(\frac{-7}{12}\) * 10^2

E. \(-\frac{0.7}{0.12}\) = \(\frac{-7}{12}\) * 10^1
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