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# Of the students who eat in a certain cafeteria, each student either

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Intern
Joined: 25 Jan 2018
Posts: 1
Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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30 Mar 2018, 02:08
I have a question. Why does nobody take into account the ones who like lima beams, do they like the brussels sprouts or not? We do not know that and for me it is a msileading question because if some of the ones who like lia beams also like brussel sprouts then we do not know how many of them do like and how many do not. So the right anwser must be E
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Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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30 Mar 2018, 04:37
bernardoassensio wrote:
I have a question. Why does nobody take into account the ones who like lima beams, do they like the brussels sprouts or not? We do not know that and for me it is a msileading question because if some of the ones who like lia beams also like brussel sprouts then we do not know how many of them do like and how many do not. So the right anwser must be E

We have table which takes into account all possible cases:
1. Those who likes lima and likes sprouts;
2. Those who likes lima and do NOT like sprouts;
3. Those who do NOT like lima and likes sprouts;
4. Those who do NOT like lima and do NOT like sprouts.

You can check almost all the solutions from previous page for that. For example, this one: https://gmatclub.com/forum/of-the-stude ... ml#p733320 So, your doubt/question is not clear.

P.S. This is a GMAT Prep question, so it's as clear and unambiguous as it gets.
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Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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15 Sep 2018, 08:26
Bunuel wrote:
dimitri92 wrote:
What is the best approach to tackle questions like these ?

Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

I'd advise to make a table:

Note that:
"2/3 dislike lima beans" means 2/3 of total dislike lima;
"of those who dislike lima beans, 3/5 also dislike brussels sprouts" means of those who dislike lima $$1-\frac{3}{5}=\frac{2}{5}$$ like sprout, or $$\frac{2}{3}*\frac{2}{5}=\frac{4}{15}$$ of total dislike lima but like sprouts. So to calculate # of students who dislike lima but like sprouts we should now total # of students (t).

(1) 120 students eat in the cafeteria --> $$t=120$$ --> $$x=\frac{4}{15}t=32$$. Sufficient.

(2) 40 of the students like lima beans --> total students who like lima + total students who dislike lima = total --> $$40+\frac{2}{3}t=t$$ --> $$t=120$$ --> $$x=\frac{4}{15}t=32$$. Sufficient.

Attachment:
Lima-Sprouts.JPG

hi Bunuel,

I reached the same answer but my values were different than yours.

Lima Beans Brussels Total
Like X/3 X-(2X/5)=3X/5
Dislike (2/3 )X 2/3*3/5=(2/5)X
Total X X X

Now as we are told that EVery student either likes or dislikes each bean. So the total of Beans like + dislike=X
and total of Brussels Like + dislike=X

Statement 1 says X=120 therefore sufficient
Statement 2 directly gives X/3=40 therefore X=120.

Is this approach correct?

Cos the answer that we are looking for is "Students who like Brussels but dislike Lima"

Will this approach furnish an answer?
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Thanks and Regards,

Honneeey.

In former years,Used to run for "Likes", nowadays, craving for "Kudos". :D

Intern
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Of the students who eat in a certain cafeteria, each student either  [#permalink]

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16 Oct 2018, 22:02
Hi!

I have a difficulty in understanding why does the table's totals don't equal? shouldn't it be that totals are like a+b=120? And instead it is sort of 200?:P If it is said that there are only 120 students in the cafeteria.
Like Dislike Total
LB 40 80 120
BS 32 48 80
Total 72 128

Thanks!
Intern
Joined: 10 Oct 2018
Posts: 6
Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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16 Oct 2018, 22:09
Hi!

I have a difficulty in understanding why does the table's totals don't equal? shouldn't it be that totals are like a+b=120? And instead it is sort of 200?:P If it is said that there are only 120 students in the cafeteria.
Like Dislike Total
LB 40 80 120
BS 32 48 80
Total 72 128

Thanks!
Intern
Joined: 07 Jan 2017
Posts: 1
Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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27 Nov 2018, 06:37
Hi,
Can some one please solve the below question in the same matrix form explained in the above posts.

a class took 2 tests,one in physics and the other in math. (1/4)th of the students failed in physics.60% of those passed in physics also passed in math. if 300 students took both the tests and 140 students passed in exactly one of the two subjects, how many failed in both?
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Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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01 Dec 2018, 02:29
dimitri92 wrote:
Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

(1) 120 students eat in the cafeteria
(2) 40 of the students like lima beans

Attachment:
del5.jpg

"Of the students who eat in a certain cafeteria, ... "
Say T students eat in the cafeteria

"Of these students, 2/3 dislike lima beans"
(2/3)*T dislike Lima

"and of those who dislike lima beans, 3/5 also dislike brussels sprouts"
Of (2/3)T, (3/5) also dislike brussels so (3/5)*(2/3)T = (2/5)T dislike brussels
We don't know about the rest of the (T/3) that how many of them dislike brussels.

"How many of the students like brussels sprouts but dislike lima beans?"
(2/3)T dislike Lima and (2/5)th of these like Brussels (since (3/5)th of these do not like Brussels)
So (4/15)T dislike Lima but like Brussels.

(1) 120 students eat in the cafeteria
This gives us the value of T. We need to find (4/15)T which we can now. Sufficient

(2) 40 of the students like lima beans
(2/3)T dislike Lima so (1/3)T like Lima. If (1/3)T = 40, we get T = 120.
Again, we can now find (4/15)T. Sufficient.

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Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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19 Jan 2019, 09:13
dimitri92 wrote:
Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes or dislikes brussels sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussels sprouts. How many of the students like brussels sprouts but dislike lima beans?

(1) 120 students eat in the cafeteria
(2) 40 of the students like lima beans

This is overlapping sets, since all the students like and dislikes both foods. I drew a table with the givens and then filled in with information from 1) and 2)

Both 1) and 2) give us sufficient information to solve for x, so C
It's pretty quick to check the table to make sure everything matches up.
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Re: Of the students who eat in a certain cafeteria, each student either  [#permalink]

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25 Jan 2019, 06:35
Wow, this is an interesting sum. Thanks for the answer) Mathematics is my hobby. I study medicine at university. In exchange for your help, I would like to recommend the website https://au.edusson.com/essay-help on which I ordered a medical essay. But I am sure that professionals will also help mathematicians, because they have a lot of essay topics. At the same time prices are favorable for students.
Re: Of the students who eat in a certain cafeteria, each student either   [#permalink] 25 Jan 2019, 06:35

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