Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
04 Jan 2013, 03:06
Kudos
Bookmarks
A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
64% (02:12) correct
36%
(02:31)
wrong
based on 112
sessions
History
Date
Time
Result
Not Attempted Yet
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a < b and both a and b are positive values then what is the area of the quadrilateral?
(1) b + c = 6
(2) The quadrilateral is a rectangle.
(1) b + c = 6
(2) The quadrilateral is a rectangle.
04 Jan 2013, 04:41
Kudos
Bookmarks
trex16864
There is a problem with this question. We are given that a + c = 12 and (1) says that b + c = 6, thus a = b + 6, which implies that a > b. But the stem says that a < b. I guess it should be a > b instead of a < b.
In this case the question would be:
On a graph the four corners of a certain quadrilateral are (a,5), (b,5), (a,0) and (b,0). If a + c = 12, a > b and both a and b are positive values then what is the area of the quadrilateral?
Look at the diagram below:
Attachment:
Quadrilateral.PNG [ 9.43 KiB | Viewed 5664 times ]
(1) b + c = 6. Since a + c = 12 and b + c = 6, then a - b = 6. Area = 5*6=30. Sufficient.
(2) The quadrilateral is a rectangle. We already know that. Not sufficient.
Answer: A.
Hope it's clear.
General Discussion
My solution:
Given the information in the question we can already conclude, that the quadriliteral is a rectangle with a width of 5. We need to figure out the length of the rectangle in order to find the area.
(1) with
I) \(a + c = 12\)
II) \(b + c = 6\)
we can I) - II) => \((a-b) = 6\)
Length = Distance [(a;5) (b;5)] = Distance [(a;0) (b;0)] =
= SQR [ \((a-b)^2 + (5-5)^2\) ]
= SQR [ \(6^2 + 0^2\) ]
= 6
=> \(Area = 6 * 5 = 30\) sufficient
(2) We already know that we have a rectangle. The statement gives us no further information about the length. Not sufficent
Hence A
Given the information in the question we can already conclude, that the quadriliteral is a rectangle with a width of 5. We need to figure out the length of the rectangle in order to find the area.
(1) with
I) \(a + c = 12\)
II) \(b + c = 6\)
we can I) - II) => \((a-b) = 6\)
Length = Distance [(a;5) (b;5)] = Distance [(a;0) (b;0)] =
= SQR [ \((a-b)^2 + (5-5)^2\) ]
= SQR [ \(6^2 + 0^2\) ]
= 6
=> \(Area = 6 * 5 = 30\) sufficient
(2) We already know that we have a rectangle. The statement gives us no further information about the length. Not sufficent
Hence A
