HKD1710 wrote:

Over the last three years a scientist had an average (arithmetic mean) yearly income of $45,000. The scientist earned \(1\frac{1}{2}\) times as much the second year as the first year and \(2\frac{1}{2}\) times as much the third year as the first year. What was the scientist's income the second year?

(A) $9,000

(B) $13,500

(e) $27,000

(D) $40,500

(E) $45,000

3 Years AM = 45000, Total Sum will be 135000

Given Y2 = 3/2 Y1

Y3 = 5/2 Y1

Y1 + Y2 + Y3 = 135000

substitute for above

Y1 = 27000

Y2 = 3/2 Y1 = 40500

D

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