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Over the last three years a scientist had an average (arithmetic mean)
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01 Dec 2018, 09:07
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Over the last three years a scientist had an average (arithmetic mean) yearly income of $45,000. The scientist earned \(1\frac{1}{2}\) times as much the second year as the first year and \(2\frac{1}{2}\) times as much the third year as the first year. What was the scientist's income the second year? (A) $9,000 (B) $13,500 (e) $27,000 (D) $40,500 (E) $45,000 Project PS Butler : Question #52 Subscribe to get Daily Email  Click Here  Subscribe via RSS  RSS
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Re: Over the last three years a scientist had an average (arithmetic mean)
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01 Dec 2018, 09:25
Average of 3 years = 45,000$ Total income in 3 years = 135,000$ Let the income in first year be x. Now, x+3/2x+5/x = 135,000 x = 27,000$ Income in second year = 1.5(27000) = 40,500$ D is the answer.
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Re: Over the last three years a scientist had an average (arithmetic mean)
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01 Dec 2018, 16:21
Let first year salary be x then second year salary = 1.5x Third year = 2.5 x Average salary for three years is 45000 which means total salary for 3 years = 45000(3) x+1.5x+2.5x=135000 5x=135000 x=27000
Second year salary is 1.5x= 1.5*27000 =$40,500
D is the correct answer



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Over the last three years a scientist had an average (arithmetic mean)
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02 Dec 2018, 04:00
Average income for three months is 45000, then total income for three months is 45,000*3 = 135,000
"The scientist earned \(1\frac{1}{2}\) times as much the second year as the first year"
So,
Let First year be \(x\)
Then second Year is \(\frac{3x}{2}\)
"and \(2\frac{1}{2}\) times as much the third year as the first year"
So third Year is \(\frac{5x}{2}\)
\(\frac{X}{1} +\frac{3x}{2}+\frac{5x}{2} = 135,000\)
\(\frac{10x}{2}\) = \(135,000\)
\(10x = 270,000\)
\(x = 27,000\)
Second year = \(\frac{3}{2} * 27000 = 40,500\)



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Re: Over the last three years a scientist had an average (arithmetic mean)
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10 Feb 2019, 21:09
HKD1710 wrote: Over the last three years a scientist had an average (arithmetic mean) yearly income of $45,000. The scientist earned \(1\frac{1}{2}\) times as much the second year as the first year and \(2\frac{1}{2}\) times as much the third year as the first year. What was the scientist's income the second year?
(A) $9,000 (B) $13,500 (e) $27,000 (D) $40,500 (E) $45,000
3 Years AM = 45000, Total Sum will be 135000 Given Y2 = 3/2 Y1 Y3 = 5/2 Y1 Y1 + Y2 + Y3 = 135000 substitute for above Y1 = 27000 Y2 = 3/2 Y1 = 40500 D
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Over the last three years a scientist had an average (arithmetic mean)
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17 Jun 2019, 05:42
Over the last three years a scientist had an average (arithmetic mean) yearly income of $45,000. The scientist earned \(1\frac{1}{2}\) times as much the second year as the first year and \(2\frac{1}{2}\) times as much the third year as the first year. What was the scientist's income the second year?
(A) $9,000 (B) $13,500 (e) $27,000 (D) $40,500 (E) $45,000
guys, I got this one right, but this sort of language always confuses me.. I am getting used to it, but not being a native leads me to a confusion. I sometimes think of it as F = 3/2 S and then later on, thinking logically, I changed it to S= 3/2 F (as usually salary increments), but then its the GMAT, so one should be prepared... can anyone help me find a way to debug such language ?
any help from language experts will be appreciated too..




Over the last three years a scientist had an average (arithmetic mean)
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17 Jun 2019, 05:42






