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17 Jun 2021, 01:08
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
50% (03:04) correct
50%
(02:49)
wrong
based on 171
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There are two containers A and B filled with mentha oil with different prices and with volumes 140 and 60 liters respectively. Equal quantities are drawn from both A and B in such a manner that the oil drawn from A is poured in into B and oil drawn from B is poured into A. After doing so, the price per liter becomes equal in both containers. What is the (equal) quantity that was drawn?
A. 21 liters
B. 27 liters
C. 35 liters
D. 42 liters
E. 45 liters
A. 21 liters
B. 27 liters
C. 35 liters
D. 42 liters
E. 45 liters
12 Jul 2021, 14:02
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In order to have the same price ratio in both mixtures must be the same.
\(\frac{140-x}{x}=\frac{x}{60-x}\)
\(x^2=140*60-200x+x^2\)
\(x=42\)
\(\frac{140-x}{x}=\frac{x}{60-x}\)
\(x^2=140*60-200x+x^2\)
\(x=42\)
13 Sep 2021, 23:09
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Bunuel
Say the oil in 140 lts container is cheaper and the oil in 60 ltr container is more expensive.
After mutual replacement, overall price becomes the same. This means that the concentration of either ingredient (one kind of oil) is the same in both mixtures.
Say, we remove x litres from each and replace in the other.
Concentration of expensive oil in both containers should be equal. So
\(\frac{x}{140} = \frac{(60 - x)}{60} \)
x = 42 liters
Answer (D)
Note that we could have done the same thing with the concentration of cheaper oil and we would have got the same answer. In mixtures, we need to deal with the concentration of any one ingredient e.g. with concentration of sugar in sugar solution.
