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705-805 Level|   Graphs|   Math Related|            
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KanikaJain
Shouldn't the answer to the second question be G?
­You are correct.

OFFICIAL EXPLANATION:



RO1:

For each of the 7 groups, adding a worker will increase the group’s mean salary if and only if that worker’s salary exceeds the group’s current mean salary. Each group plans to hire a new worker at the group’s median salary. So, assuming no other relevant factors change, adding the worker as planned will increase the group’s mean salary if and only if the group’s median salary now exceeds its mean salary. The graph shows that this holds for exactly three of the groups—Group A, Group C, and Group G. So, for each of exactly 3 of the groups, adding a worker as planned will increase the group’s mean salary.

The correct answer is 3.

RO2:

Each of the groups has the same number of workers. So, if each group adds exactly one worker, the resulting percentage increase in mean salary will be highest for the group for which the new worker’s salary is highest as a percentage of that group’s current mean salary. Each group plans to add a worker at its own median salary. Thus, assuming no other relevant factors change, adding the worker as planned will yield the greatest percentage increase in the group’s mean salary for the group whose median salary is now the highest as a percentage of its mean salary. The graph shows that this is Group G, whose median salary is almost 110% of its mean salary.

The correct answer is G.­
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Let arithmetic mean be A and Median be x% of A and T be total employee

New salary = (AT+x%*A)/(T+1) ; so New Salary= A(T+x%)/(T+1)

so X is more than 100% than new salary will be greater than A and further greater the x higher the % increase.
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For group A, Median is equal to Mean. So, adding employee with median salary shall not increase the mean salary. So, answer should be 2
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SR4896
For group A, Median is equal to Mean. So, adding employee with median salary shall not increase the mean salary. So, answer should be 2
­Hi SR4896,
For Group A, you would find that the median is more than 100% (slightly). Thus it becomes greater than the mean.
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karishma GMATNinja marty - Can you please explain this one.
How are we applying the concept of Mean and Median in this question and also how do we solve this one
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nikitathegreat
karishma GMATNinja marty - Can you please explain this one.
How are we applying the concept of Mean and Median in this question and also how do we solve this one

It seems scrantonstrangler has a good explanation above as well as the official explanations posted. Is there something not clear?
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I was able to do this in 30 seconds, and here is how you can do it as well:

Observe (eyeball) that any new median that is above 100% of the mean will definitely be greater than the mean (basically saying median is 1.xx times the mean. Hence, by eyeballing we have 3 groups (1st answer). Now the greatest positive change/deviation from the mean will be observed with the greatest value as a percentage to the mean.. clearly G is ~110% of its mean.. (also visually the tallest) (Answer 2)

Hope it helps!
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nikitathegreat
karishma GMATNinja marty - Can you please explain this one.
How are we applying the concept of Mean and Median in this question and also how do we solve this one
I was able to do this in 30 seconds, and here is how you can do it as well:

Observe (eyeball) that any new median that is above 100% of the mean will definitely be greater than the mean (basically saying median is 1.xx times the mean). Hence, by eyeballing we have 3 groups (1st answer). Now the greatest positive change/deviation from the mean will be observed with the greatest value as a percentage to the mean.. clearly G is ~110% of its mean.. (also visually the tallest) (Answer 2)

Hope it helps!
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It's pictorially very ambiguous to dentify if A is equal to 100% or greater. Spent good one minute to figure it out.

Similarly in many questions it's difficult to make out if the count is eg 2.6 or 2.7.

Any clues for this please.
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RishiSpi
It's pictorially very ambiguous to dentify if A is equal to 100% or greater. Spent good one minute to figure it out.

Similarly in many questions it's difficult to make out if the count is eg 2.6 or 2.7.

Any clues for this please.

It might not be very clear in this image, but in the actual high-resolution graph, it’s quite clear that A is above 100%. On the real exam, the visuals are much sharper, so this kind of ambiguity shouldn’t be an issue.



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