let x be the length (where the house boundary at) y be the width of the garden
method: if we have the sum of x and y we can get the maximum of the product (xy)
you can search this on youtube for more details:
[size=100]Maximum product from two numbers that sum to 18[/size]
from the question we know that
2y+x=96
and we want to get the maxi of xy
plug x=96-2y into xy
we have:
xy = 96y-2(y^2)
to get the maxi, we need a
quadratic function, which looks like f(x) = a(x-b)^2+cthis way when x = b, we have c, the constant, as our maxithus,xy = -2(y^2-48y) = -2(y^2-48y+24^2)+2*24^2 = -2(y-24)^2+1152 (our quadratic function)
i.e. when y = 24, 1152 is the maxi of xy
and when y = 24, x = 48
therefore the answer (48,1152)
Sajjad1994
Padraig has a rectangular vegetable garden bordered by his house on one side and a picket fence on the three other sides. Currently, Padraig’s house can provide a boundary of up to 50 feet for one side of the garden and he has already used 75% of 96 feet of available picket fence to enclose the other three sides of the garden. If the picket fence can only be arranged in whole foot dimensions, what would be the length of the boundary of the garden bordered by Padraig’s house required to produce the largest possible rectangular vegetable garden should he extend the three other dimensions of it using the remaining feet of picket fence?
Select the length of the garden bordered by the house in feet and largest possible vegetable garden area in square feet after the fence is extended. Make only two selections, one in each column.