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14 Aug 2019, 00:10
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
68% (01:57) correct
33%
(02:20)
wrong
based on 80
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Pat bought both carrots and onions from a store. If each carrot cost $1.10, each onion cost $0.50, and the purchase of carrots and onions totaled $11.00, what total number of carrots and onions did Pat buy?
A. 10
B. 11
C. 12
D. 13
E. 16
A. 10
B. 11
C. 12
D. 13
E. 16
15 Aug 2019, 07:07
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A) Works, 10 carrots, 0 onions, total 11$. But Bonuel said that both were bought.
So...
11$ has no decimals, start with carrots. The only number that works is 5, to get 5.5$.
You have 5.5$ left. 5.5/0.5 is 55/5 or 11.
11+5 = 16
Therefore,
E
Posted from my mobile device
So...
11$ has no decimals, start with carrots. The only number that works is 5, to get 5.5$.
You have 5.5$ left. 5.5/0.5 is 55/5 or 11.
11+5 = 16
Therefore,
E
Posted from my mobile device
30 Aug 2019, 11:27
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Bunuel
Pat bought both carrots and onions from a store. If each carrot cost $1.10, each onion cost $0.50, and the purchase of carrots and onions totaled $11.00, what total number of carrots and onions did Pat buy?
A. 10
B. 11
C. 12
D. 13
E. 16
A. 10
B. 11
C. 12
D. 13
E. 16
1.1c+0.5o=11$
Now you know there is a unique solution to this equation. So either you can try all possible combinations or you can realize that the total is an integer. So the gap between the two which 0.6$ must come to an integer. So 0.6*5 gives you 3$. So the gap between (c and o) must be 5 at the least. 11 of onion and 5 of carrots give you 5.5+5.5=11.
Hence E.
