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# Pat, Kate, and Mark charged a total of 162 hours to a

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Manager
Joined: 30 Jul 2007
Posts: 130
Pat, Kate, and Mark charged a total of 162 hours to a [#permalink]

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02 Oct 2008, 14:59
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Pat, Kate, and Mark charged a total of 162 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much as Mark, how many more hours did Mark charge to the project than Kate?

18
36
72
90
108
Intern
Joined: 29 Sep 2008
Posts: 46
Re: SZ-PS - time charged [#permalink]

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02 Oct 2008, 19:32
E
k + 2k + 6k = 162. k = 18. mark = 6k = 108
Manager
Joined: 30 Jul 2007
Posts: 130
Re: SZ-PS - time charged [#permalink]

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02 Oct 2008, 19:40
aim2010 wrote:
E
k + 2k + 6k = 162. k = 18. mark = 6k = 108

Thats exactly what I did, but its not the OA.
Intern
Joined: 29 Sep 2008
Posts: 46
Re: SZ-PS - time charged [#permalink]

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02 Oct 2008, 20:07
aim2010 wrote:
E
k + 2k + 6k = 162. k = 18. mark = 6k = 108

my bad, the questions asks what is 6k - k = 5k = 90. D.
VP
Joined: 30 Jun 2008
Posts: 1019
Re: SZ-PS - time charged [#permalink]

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02 Oct 2008, 20:24
sarzan wrote:
Pat, Kate, and Mark charged a total of 162 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much as Mark, how many more hours did Mark charge to the project than Kate?

18
36
72
90
108

Agree with above approach. here is another way to do it (bit longer though)
P = 2K or K = P/2 and P = M/3 or M = 3P

P + K + M = 162
P + P/2 + 3P = 162

2P + P + 6P = 162*2
9P = 162*2
P = 18*2 = 36

K = 36/2 = 18 AND M = 3*36 = 108

M-K = 90
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VP
Joined: 18 May 2008
Posts: 1203
Re: SZ-PS - time charged [#permalink]

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02 Oct 2008, 22:07
P=2K=1/3M
P+P/2+3P=162
P=36, M=108,K=18
M-K=90
Ans is D
Re: SZ-PS - time charged   [#permalink] 02 Oct 2008, 22:07
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# Pat, Kate, and Mark charged a total of 162 hours to a

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