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# Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC

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Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
nipunjain14 wrote:
bc = 4- 3 = 1
cd= 6-1 = 5

Ans:E

How did you get the second part (CD = 6-1 = 5) ?

Thanks,
Leon
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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
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leonidbasin1 wrote:
nipunjain14 wrote:
bc = 4- 3 = 1
cd= 6-1 = 5

Ans:E

How did you get the second part (CD = 6-1 = 5) ?

Thanks,
Leon

BC = AC- AB = 4 - 3 = 1
CD = BD - BC = 6 -1 = 5

Hope this is now clear.
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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
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Bunuel wrote:
Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC = 4 cm, and BD = 6 cm, what is CD, in centimeters?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Given: The points are in order from A to D.
Given: Distance A to B = 3cm, Distance A to C = 4cm, Distance B to D = 6cm

Just draw a line:

A-----B-----C-----D
A--3--B--1--C--5--D

OA
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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
AC-AB=BS
3-2=1
BD-BC=CD
6-1=5

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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
Bunuel wrote:
Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC = 4 cm, and BD = 6 cm, what is CD, in centimeters?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC = 4 cm, and BD = 6 cm, what is CD, in centimeters?

A-----------B-------------C--------------D
----3------- --------------6-------------
-------------4-------------

CD = AB + BD - AC = 3 + 6 -4 = 9 -4 =5

IMO E
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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
Nice as a warm up question, thanks!

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Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
--------A------B-------C-------D---

mark the values as you read the question:

AB is 3, AC is 4, (BC=AC-AB) meaning BC is 1

BD is 6, (CD=BD-BC) as we know BC is 1, thus, CD is 5.
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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
Since points A, B, C, and D lie on a line in that order, you can consider the segments as follows:

AB + BC = AC
3 cm + BC = 4 cm
BC = 4 cm - 3 cm
BC = 1 cm

Now, since points B, C, and D are collinear, you can use the fact that BD = BC + CD:

BD = BC + CD
6 cm = 1 cm + CD
CD = 6 cm - 1 cm
CD = 5 cm

So, CD is 5 centimeters.
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Re: Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
Bunuel wrote:
Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC = 4 cm, and BD = 6 cm, what is CD, in centimeters?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

BC = 4-3=1
CD = 6 -1 =5
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Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
Bunuel wrote:
Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC = 4 cm, and BD = 6 cm, what is CD, in centimeters?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5

Bunuel question can be tricky if someone ask that A B C D can be in any format in the line, then what is the difference between minimum and maximum possible distance of CD ??
Points A, B, C, and D, in that order, lie on a line. If AB = 3 cm, AC [#permalink]
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