Bunuel
Positive integer x has n factors; 3x has 3 factors; Which of the following values can n take?
I. 1
II. 2
III. 3
A. I only
B. II only
C. I or II
D. II or III
E. I or III
Notice that 3x must be a perfect square since only perfect squares have an odd number of factors. Furthermore, 3x must be the square of a prime number since only squares of prime numbers have 3 factors. That is, if p is a prime, then p^2 has 3 factors, namely, 1, p, and p^2.
Since 3x is the square of a prime number, we see that x must be 3 so that 3x = 9. Since x = 3 and 3 has 2 factors, then n must be 2.
Alternate Solution:
Let’s go over Roman numerals I and III:
Roman Numeral I: x has only 1 factor
The only positive integer with 1 factor is 1 itself; but 3(1) = 3 does not have 3 factors. This is impossible.
Roman Numeral III: x has 3 factors
If x is a number with 3 factors, then 3x will have more than 3 factors. For instance, x = 9 has 3 factors and 3x = 27 has 4 factors. x = 4 has 3 factors and 3x = 12 has 6 factors. This is impossible as well.
The only remaining possibility is n = 2.
Answer: B