Distance Interpretation of the Absolute Value Modulus:
(1st) Since the Range of Values on the Number Line is a continuous range and INCLUDES the Values at the end points, the Inequality must be of the Form:
| expression | </= K
which becomes, after Opening the Modulus:
-(K) </= (expression) </= +K
(2nd) Find the Midpoint of the Continuous Range that is Shaded purple on the Number Line
(20 + 90) / 2 = 55
Each endpoint, 90 and 20, is exactly 35 Units from the Midpoint of 55 on the Number Line
(3rd) Distance Evaluation of the Absolute Value Modulus
All of the Values within the Range shown by the Purple Line on the Number Line will satisfy the Inequality we are looking for
Therefore, from the Mid-point of 55, the Value of X must be LESS THAN or EQUAL TO 35 Units away.
This is expressed by:
| X - 55 | </= 35
The Value of X must fall within the range on the Number Line that is Less Than or Equal To a DISTANCE of 35 Units away from +55 ——in EITHER Direction
-E- is the Correct Answer
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