Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Jun 0808:00 PM EDT
-10:00 PM EDT
A powerful GMAT course taught live online + 6 months of access to TTP OnDemand GMAT Masterclass included! Mon/Wed June 8, 2026 →August 12, 2026 8:00pm-10:00pm EST
Jun 1006:00 AM PDT
-06:15 PM PDT
Register for the GMAT Club Virtual MBA Spotlight Fair – the world’s premier event for serious MBA candidates. This is your chance to hear directly from Admissions Directors at nearly every Top 30 MBA program..
Jun 1111:00 AM EDT
-01:00 PM EDT
TTP GMAT OnDemand gives serious students 400+ hours of expert video instruction, the full TTP course, AI support, weekly office hours, and a 715+ score guarantee—all built for elite GMAT score improvement.
28 Nov 2018, 19:16
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
67% (03:25) correct
33%
(03:20)
wrong
based on 286
sessions
History
Date
Time
Result
Not Attempted Yet
One day at a restaurant there were a total of m workers, consisting of only waiters and cooks, some of whom had college degrees and others did not. Of these workers n were cooks and 5n/4 had college degrees. If 3n/4 cooks had degrees, m/4 of the waiters did not have degrees and 30 of the workers did not have degrees, how many workers were at the restaurant?
A. 20
B. 40
C. 80
D. 100
E. 120
A. 20
B. 40
C. 80
D. 100
E. 120
29 Nov 2018, 04:26
Kudos
Bookmarks
Jazzmin
m workers, n cooks and m-n waiters...
(I) 3n/4 cooks had degrees, so n/4 cooks do not have degrees AND m/4 of the waiters did not have degrees.
so n/4+m/4=30....n+m=120....(i)
(II) 5n/4 had college degrees, so m-30 had degrees
5n/4=m-30....5n=4m-120....(ii)
substitute value of (i)...
5n=4(120-n)-120......5n=480-4n-120......9n=360.....n=40
so m = 120 - 40 = 80
C
let us solve it logically..
30 did not have degrees and from wordings we can say that there are more with degrees than without degrees..
so our answer has to be > 30*2 or >60.
Now from choices available take m as 80..
so m/4 or 80/4 or 20 cooks do not have degree.
Total 30 did not have degrees, so 30-20 or 10 waiters did not have degrees..
a) 3n/4 cooks had degrees, so n/4 did not have degree, so n/4=10...n=40
b) 5n/4 had college degrees, so 5*40/4=50 had degrees
Total degrees + no degrees = 50+30=80
C
Ofcourse it can be easily done by 2 by 2 matrix.
Attachments
set.png [ 35.1 KiB | Viewed 4874 times ]
01 Dec 2018, 01:37
Kudos
Bookmarks
Jazzmin
really an amazing question , I solved it using 2x2 matrix..
from the given matrix we can say
m/4+n/4=30
m+n=120
and 2n/4+m/4=m-n
3m=6n
m=2n
solve for m & n we get m= 80 and n=40
IMO C 80 is correct
Attachments
File comment: 2x2 matrix
cooks and waiter 2x2.xlsx [30.37 KiB]
Downloaded 111 times
