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A certain restaurant serves exactly 5 entrées—E1 through E5. Customers may order an entrée alone, but most customers order an entrée as part of a combination meal, which consists of one entrée plus extras—a side dish and drink. While the entrées vary in cost to the restaurant, the extras always have the same cost to the restaurant. The graph shows the actual cost to the restaurant for the entrée and the extras as a percent of the price charged for the meal.
Based on the information provided, select from each drop-down menu the option that creates the most accurate statement.
Of the five combination meals, the meal with entrée has the highest price.
Of the five combination meals, the sale of a single meal with entrée nets the least profit.
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A certain restaurant serves exactly 5 entrées—E1 through E5. Customers may order an entrée alone, but most customers order an entrée as part of a combination meal, which consists of one entrée plus extras—a side dish and drink. While the entrées vary in cost to the restaurant, the extras always have the same cost to the restaurant. The graph shows the actual cost to the restaurant for the entrée and the extras as a percent of the price charged for the meal.
Based on the information provided, select from each drop-down menu the option that creates the most accurate statement. Of the five combination meals, the meal with entrée has the highest price.
Of the five combination meals, the sale of a single meal with entrée nets the least profit.
We are shown the cost to a restaurant as a percentage of meal price.
So if a meal price is $30, and cost to the restaurant for that meal is 70%, the cost to the restaurant for that meal will be $21 and the restaurant will make $9 profit on that meal. The $21 cost will be a sum of cost of entree (say $11) and a fixed cost of sides of $10.
Cost to restaurant of entrees are different but cost of 'extras' are always same (say $10 for all meal combinations). So assuming meal prices of combinations are E1, E2, E3, E4 and E5,
We know that 15% of E1 = 20% of E2 = 25% of E3 = 25% of E4 = 20% of E5 = Constant (price of extras i.e. $10)
Hence, E1 is highest. (because its 15% is equal to higher percentage of others)
Of the five combination meals, the meal with entrée ___ has the highest price.
ANSWER: E1
Of the five combination meals, the sale of a single meal with entrée ___ nets the least profit.
The least profit will be made by a meal with the smallest price and maximum cost. E3 and E4 have the same combination meal price since cost of sides is 25% of the price in both. But cost of entree is higher in E4. It is 40% of meal price. Hence profit in E4 will be lowest.
A certain restaurant serves exactly 5 entrées—E1 through E5. Customers may order an entrée alone, but most customers order an entrée as part of a combination meal, which consists of one entrée plus extras—a side dish and drink. While the entrées vary in cost to the restaurant, the extras always have the same cost to the restaurant. The graph shows the actual cost to the restaurant for the entrée and the extras as a percent of the price charged for the meal.
Based on the information provided, select from each drop-down menu the option that creates the most accurate statement. A. Of the five combination meals, the meal with entrée _______ has the highest price.
B. Of the five combination meals, the sale of a single meal with entrée _________ nets the least profit.
On basis of the Graph, the Total Price of a particular Combination Meal (E1/2/3/4/5) can be divided into :-
Originally posted by SKDEV on 19 Jun 2024, 00:25.
Last edited by SKDEV on 19 Jun 2024, 06:37, edited 1 time in total.
more understandable explanation for first part-
since price of all extras are same: 15% of meal1 = 20% of meal2 = 25% of meal3 = 25% of meal4 = 20% of meal5 = K(assume) so, price of meal1 = 100k/15, price of meal2 = 100k/20 and so on.....
now E1 entre price = 30% of meal1 => 30/100 * 100k/15 =>2k and similarly we can find entre price for all the rest!
This is how people are directly concluding we can see the ratio of entre to extra, whichever is highest is our answer
So there is a line that caught my eye 'extras cost the same to the restaurant' ...and we have the % given with proportion to the meal price charged. Let's take extra cost to be $60.. Now for E1, extra is 15% of the total price 60 is 15%, so 100% is $400,
Same way we can do for other meals but i know other meals will cost lesser. Eg: E2 - $60 will be 20% of the total meal price, overall price comes out to be $300. Hence for (1) ans is E1
A certain restaurant serves exactly 5 entrées—E1 through E5. Customers may order an entrée alone, but most customers order an entrée as part of a combination meal, which consists of one entrée plus extras—a side dish and drink. While the entrées vary in cost to the restaurant, the extras always have the same cost to the restaurant. The graph shows the actual cost to the restaurant for the entrée and the extras as a percent of the price charged for the meal.
Based on the information provided, select from each drop-down menu the option that creates the most accurate statement. A. Of the five combination meals, the meal with entrée _______ has the highest price.
B. Of the five combination meals, the sale of a single meal with entrée _________ nets the least profit.
On basis of the Graph, the Total Price of a particular Combination Meal (E1/2/3/4/5) can be divided into :-
Originally posted by cheshire on 22 Aug 2025, 14:05.
Last edited by cheshire on 22 Aug 2025, 14:06, edited 1 time in total.
Profit % = 100% − Total Cost %
Total Cost % = Entrée cost % + Extras cost % (from the bar chart). The chart already shows these costs as a percentage of the meal price, so you don’t need to know the actual prices.
Since the extras always have the same cost to the restaurant, that cost must be lowest as a percentage of the highest price charged for a combination meal. The graph shows the extras cost only about 15% of the price charged for the combination meal with entrée E1, but at least 20% of the price charged for each of the other combination meals. So, the combination meal with entrée E1 has the highest price.
The correct answer is E1.
RO2:
Let's assume that apart from the costs shown in the graph, any other costs to the restaurant are the same for each combination meal served. Out of the sales price of a combination meal, the percentage profits to the restaurant are then lower for combination meals whose total percentage costs shown in the graph are higher. The total percentage costs shown in the graph are highest for the combination meal with entrée E4, so this meal must net the least profit as a percentage of its sales price. Next, note that the graph shows that the extras cost at least as high a percentage of this meal’s sales price as of any of the other combination meals’ sales prices. That means this meal must have a sales price no higher than any of the other combination meals do. So, because the meal with entrée E4 nets the least profit as a percentage of its sales price, and that sales price is no higher than any other combination meal’s sales price, the meal with entrée E4 must net the least total amount profit per meal served.
Hence, E1 is highest. (because its 15% is equal to higher percentage of others), this part.
I got the Q wrong had switched the answers, my understanding was that for First Blank it would be E4 as it is the highest % of meal price hence cost to restaurant, and the higher the cost to restaurant the higher they would charge the price of the meal, similar logic for blank 2
KarishmaB
We are shown the cost to a restaurant as a percentage of meal price.
So if a meal price is $30, and cost to the restaurant for that meal is 70%, the cost to the restaurant for that meal will be $21 and the restaurant will make $9 profit on that meal. The $21 cost will be a sum of cost of entree (say $11) and a fixed cost of sides of $10.
Cost to restaurant of entrees are different but cost of 'extras' are always same (say $10 for all meal combinations). So assuming meal prices of combinations are E1, E2, E3, E4 and E5,
We know that 15% of E1 = 20% of E2 = 25% of E3 = 25% of E4 = 20% of E5 = Constant (price of extras i.e. $10)
Hence, E1 is highest. (because its 15% is equal to higher percentage of others)
Of the five combination meals, the meal with entrée ___ has the highest price.
ANSWER: E1
Of the five combination meals, the sale of a single meal with entrée ___ nets the least profit.
The least profit will be made by a meal with the smallest price and maximum cost. E3 and E4 have the same combination meal price since cost of sides is 25% of the price in both. But cost of entree is higher in E4. It is 40% of meal price. Hence profit in E4 will be lowest.
Hence, E1 is highest. (because its 15% is equal to higher percentage of others), this part.
I got the Q wrong had switched the answers, my understanding was that for First Blank it would be E4 as it is the highest % of meal price hence cost to restaurant, and the higher the cost to restaurant the higher they would charge the price of the meal, similar logic for blank 2
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Extras (the blue bars) have the same dollar cost in every combo. The blue bar is “extras as a percent of price.” If the same dollar amount is 15% of the price (E1), the price must be higher than when that same dollar amount is 20% or 25% of the price (E2 to E5). That is why E1 has the highest price, even though its cost percentage is not the highest.
For example, say the extras cost the restaurant $15 for every combo. Price = 15 divided by (extras percent as a decimal): E1: 15% extras, price = 15/0.15 = 100 E2: 20% extras, price = 15/0.20 = 75 E3: 25% extras, price = 15/0.25 = 60 E4: 25% extras, price = 15/0.25 = 60 E5: 20% extras, price = 15/0.20 = 75
So E1 has the highest price.
Second drop down: E3 and E4 have the same price (both 60).
E3 total cost is 60%, so profit is 40% of 60 = 24. E4 total cost is 65%, so profit is 35% of 60 = 21.
I am not sure why computing profits is necessary here. Extra is has fixed cost. hence lowest the share of the overall price it is higher the price is. Hence E1. same can be applied for E4.