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2 months until SP Jain PGPM R1.
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7 months untill ISB PGP and IIM A PGPX R1

All the best everybody. You may contact me for any kind of guidance.
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hi all, as a freshman, i wanna know if it works if I do the PS question directory by topics, and then select the most kudos to practice. Compared with doing OG.
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Where can I find an explanation of (8-1)^11 leads to remainder 3 from this post: what-is-the-remainder-of-126493.html
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Where can I find an explanation of (8-1)^11 leads to remainder 3 from this post: what-is-the- ... 26493.html
You have to look at the pattern of 3^X

Specifically look at how the unit digit changes.

3^1 = 3
3^2= 9
3^3= 27
3^4 = 81
3^5 = 243

The pattern is the same every 4 powers. So you you divide 71 by 4 and then look at the remainder. 71/4 = 17 + 3/4

So you look at the unit digit in the 3rd place, which will be 7. If 7 is the unit digit, then that number divided by 5 will have a remainder of two.

Typing on my phone I botched the math, it’s actually 77 (7x11), but I hope you still follow
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is-the-median-of-the-a-b-quiz-scores-greater-than-the-mean-of-the-425848.html#p3366805

I am strggling to pick number for these kinda questions

Can anyone teach me how to pick numbers
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wolfof6thstreet
You have to look at the pattern of 3^X Specifically look at how the unit digit changes. 3^1 = 3 3^2= 9 3^3= 27 3^4 = 81 3^5 = 243 The pattern is the same every 4 powers. So you you divide 71 by 4 and then look at the remainder. 71/4 = 17 + 3/4 So you look at the unit digit in the 3rd place, which will be 7. If 7 is the unit digit, then that number divided by 5 will have a remainder of two.
How did you arrive at 71?
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Typo on my part. Don’t know how to edit previous post. My apologizes. Let me rewrite it to fix the error. One sec
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Looking at the question. I misread it initially. This question actually would never be on the test, but in case you’re wondering it’s going off the pattern of 3^x.

Knowing that the unit digit repeats every 4 powers. So if you can take X/4 and turn it into x/4 = 4n + k then you can solve the question by figuring out what k is since it will be between 0-3, inclusively.

In this situation, x= 7^11

So (7^11/4) is what we need to put into 4n+k format. To do this it’s easier to view 7 as (8-1). To then break this down further, you need to understand the concept of negative remainders… which will never show up on the actual exam.

Originally I thought the question was ((3^7)^11) which would be 3^77

This is a question that could be tested since it’s quite easy to see how to turn 77/4 into 4n + k

It would be 4(19) + 1

So you would look for the unit digit of 3^1 and then see what the remainder would be if dividing by 5
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Hi, Just curious about the whole process. Can the ques asked in SAT exam can be reframed in real Gmat exam?
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Hello guys, I would like your help considering my MBA. It’s a 5 questionnaire. It would be very helpful to answer. Thanks in advance. link:https://docs.google.com/forms/d/e/1FAIpQLSfY4XYDINoowopBEh7CVx8OSwGb8lDo0OKBzqTLe2zot3VHvA/viewform?usp=sf_link
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In the range of 8 integer in list M is 14,and the least integer in the least is 5. In list M,the amount by which the greatest possible average of the integers exceeds the least possible average of the integer is what fraction of the range of integers? can anyone help me with this?
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yes

how did you get it?
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A1= 5
A8 = 14+ 5= 19
For greatest average,
5+ 19* 7 / 8 = 17.25
For least average ,
5*7 + 19 / 8 = 6.75
Required fraction = 10.5/14= 3/4 .

Source?
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