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03 May 2024, 22:09
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In the question shared in the screenshot - I eliminated option C because ’a’ >= 2 means that ’a’ could be 3 as well. And we know that doesn’t satisfy the given condition that ’a’ has to be even. That’s why I selected option E.
I think the question is confusing that way. Please clarify
I think the question is confusing that way. Please clarify
03 May 2024, 23:03
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ak898989
In the question shared in the screenshot - I eliminated option C because ’a’ >= 2 means that ’a’ could be 3 as well. And we know that doesn’t satisfy the given condition that ’a’ has to be even. That’s why I selected option E. I think the question is confusing that way. Please clarify
(a+1)(b-5)=0 (a-1) and (b-5) can be 0
or
(a-1)#0 and (b-5)=0
(a-1)=0 and (b-5)#0
As a must be even, for this equation to hold true, (a-1)#0 and (b-5)=0
Means b=5
a +b = 5+even value of a (2,4…..)
Hence a+b >=7
