Yusa
Can you please expulsin ?
St.1 is quite straight forward and its not sufficient.
St.2y and (z -1 ) are positive number as both lie to the right of |x+1| (modulus is always non negative).
Also, as y < z - 1, we can conclude that z lies right on the number line compared to y.
So, the relative position of y and z on the number line is
----- y ----- z ------
|x + 1| is less than y.
Therefore we can infer that the distance between x and -1 is less than the value of y.
Regardless of which side of -1 ’x’ lies, the value of ’x’ will always be less than the value of y.
We can visualize this by plotting x , y and -1 on the number line.
----- -1 ----- x ----- y ------
----- x ----- -1 ----- y ------
Hence we can conclude that x < y < z
Option B