Yusa
Yes correct, but how you do it ?
While you can find the percentage change for each options, I would recommend you do some observations and limit the number of options to test.
What observations can we make ?
Between the subsequent graphs, the change is either of three levels (6 points) or of four levels (8 points).
Now the percentage shift will be - change divided by the value of the previous level .
Hence, lower the value of the previous level, greater the percentage change will be.
Now, let’s see what the change is between the subsequent graphs
1 & 2 ⇒ Change : 4 levels ( or 8 points) | Previous Point ⇒ 20
2 & 3 ⇒ Change : 3 levels ( or 6 points) | Previous Point ⇒ 12
3 & 4 ⇒ Change : 4 levels ( or 8 points) | Previous Point ⇒ 18
4 & 5 ⇒ 3 levels ( or 6 points) | Previous Point ⇒ 10
5 & 6 ⇒ 4 levels ( or 8 points) | Previous Point ⇒ 16
Among all the changes, the greatest change can only be between either 4 & 5 or 5 & 6. This is because for the same level change the previous point is least for these two cases.
Hence we only need to test option D and option E and level the rest.
Option D = 6/10 = 0.6 (or 60%)
Option E = 8/16 = 0.5 (or 50%)
Hope this makes sense !
Realized there is a typo

: level the rest ⇒ leave the rest
DS Question 1 - Jan 07Is m +n^3 odd?
1) m is odd and n is even
2) m-n is odd
Source: Others | Difficulty: Hard
PS Question 1 - Jan 07The figure above represents a rectangular parking lot that is 30 meters by 40 meters and an attached semicircular driveway that has an outer radius of 20 meters and an inner radius of 10 meters. If the shaded region is not included, what is the area, in square meters, of the lot and driveway?
(A) 1,350π
(B) 1,200+400π
(C) 1,200+300π
(D) 1,200+200π
(E) 1,200+150π
Source: Official Guide | Difficulty: Medium