Practice Questions Chat

[quote="ChanSu"]Answer is B , x+y = 30 and x-y= 10. So 10 30 . Choice 1 (that’s says 28) and answer choices containing 1 is ruled out . Leaving only B.

But I still don’t understand why 42 cannot be the right answer

If the median is equal to max, range must be 0. So must be mean=median=100

Similar reasoning to 1), if the max is equal to average, range must be 0. So mean=median=100

D.

PS Question 1 - Feb 08

Each of 5 countries sends 3 people to a conference. How many 3-person committees could be chosen that do not include more than 1 representative from a single country?

A. 156
B. 270
C. 455
D. 910
E. 2730

Source: GMAT Ninja | Difficulty: Medium

DS Question 1 - Feb 08

In a survey, heights of boys and girls in School M were measured. The average (arithmetic mean) height of girls was 140 centimeters. What percent of the students surveyed were girls?

1. The average height of boys surveyed was 160 centimeters.

2. As per the survey, the average height of boys and girls combined was thrice as close to the average height of girls as it was to the average height of boys.

Source: Others(Jamboree) | Difficulty: Hard

5c3×3^3=270

B

X+y+z =. 50-Y taking the options into account, y can be 22, 14, and 8. Y cannot be 22 as x+z has to be greater than 22. But if the perimeter is 28. X+z is only 6 which is not possible. X-z is 10 so y has to be greater than 10. So C is eliminated.

D

Can I get a detailed solution?

how? can you elaborate on this ?

5c3.. first i choose the countries and from each of them i select one person out of the three. Which is 3. The same process is repeated for the other two. 5c3×3c1×3c1×3c1. Not one also includes 0 but those selections are included in this set. If there are 5 countries a b c d e, when not to select anyone from a and e. It is just selecting members from bcd

Way to do this:

15 total representatives, from 5 countries.
We want a team of 3 people, without any country repeating
Choose the first one: 15C1
Choose the second one: 12C1 (take out the chosen one, and the other 2 people from the chosen ones country)
Choose the last: 9C1 (same reduction as in 2nd)

Now, because the teams are not unique (ABC and CBA are the same), we have to remove 3! arrangements.
So total ways: 15*12*9/3!=270

B.

AbhinavKumar, hope this helps you!

1) clearly insuf.
2) xB+140G/(B+G)=z where x is the average male height
xB+140G=z(B+G)
The distance of Z is thrice as close to 140 as it is to X. So, (z-140)=1/3y and (x-z)=y

PS Question 1 - Feb 10

Susan invited 13 of her friends for her birthday party and created return gift hampers comprising one each of $3, $4, and $5 gift certificates. One of her friends did not turn up and Susan decided to rework her gift hampers such that each of the 12 friends who turned up got $13 worth gift certificates. How many gift hampers did not contain $5 gift certificates in the new configuration?

A. 5
B. 2
C. 9
D. 3
E. 7

Source: Others | Difficulty: Hard

DS Question 1 - Feb 10

If x and y are positive integers greater than 3, what is the remainder when xy is divided by 9?

(1) The positive difference between x and y is 2.
(2) x and y are both primes numbers.


Source: GMAT Club Tests | Difficulty: Other

PS Question 1 - Feb 12

120 people responded to a survey asking which type of vacation they prefer: city visits, ski trips, or beach holidays. No two trips were ranked equally by any of the respondents. If 55% of the respondents ranked beach holidays first, 25% ranked ski trips ahead of beach holidays, and 30% ranked city visits ahead of beach holidays, how many ranked beach holidays last?

(A) 6
(B) 12
(C) 24
(D) 30
(E) 54

Source: GMAT Ninja | Difficulty: Medium

DS Question 1 - Feb 12

If a ≠ b, is 1/(a-b) > ab ?

(1) |a| > |b|
(2) a < b

Source: Manhattan | Difficulty: Hard

got it! thank you saisandeep1997 and mysterymanrog

did this in my head, likely incorrect

1) two cases: if both are pos fractions, no
If one is negative integer (say b and a is positive) yes
2) similar to 1.
3) No new info. Depending on intgeer and sign, can be yes or no
Ans: E

With both information 1 & 2 it’s possible ...but one thing, a & b are integers are not given 😥

I think doing this via number line would be quickest , got answer as E, is it correct ?

DS Question 1 - Feb 15

Set D is a new set created by combining all the terms of Sets A, B, and C. No other terms are added to Set D other than those in Sets A, B, and C. What is the median of Set D?

(1) Sets A, B, and C each have a median of 125.
(2) Sets A, B, and C each have the same number of terms.

Source: Kaplan | Difficulty: Hard

PS Question 1 - Feb 15

The numbers in set P denote the distance of certain positive integers from -1 on the number line. The numbers in set Q denote the distance of the same integers from 1 on the number line. Which of the following statements is true about the standard deviation of the sets P and Q?

A. Standard Deviation (P) = Standard Deviation (Q)
B. Standard Deviation (P) = - Standard Deviation (Q)
C. Standard Deviation (P) = Standard Deviation (Q) + 2
D. Standard Deviation (P) = 2* Standard Deviation (Q)
E. None of the above

Source: Other | Difficulty: Medium

DS Question 1 - Feb 17

If A and B are integers, is N an even integer?

(1) 11A + 4B = N
(2) 5A – 4B = 2N

Source: GMATPrepNow | Difficulty: Medium

PS Question 1 - Feb 17

If the circus were to sell all of its 220 tickets for this month’s performance at its usual price, the revenue from sales would be 10% greater than that collected last month. If the circus raised the ticket price by 5% and sold only 200 tickets as a result, what percent less would last month’s revenue be compared to this month’s revenue?

A. 2
B. 5
C. 100/21
D. 110/20
E. 9/4

Source: GMAT Club Tests | Difficulty: Hard