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24 Feb 2015, 08:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
90% (00:34) correct
10%
(00:54)
wrong
based on 339
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Q is a cube. Find the volume of the cube.
(1) The total surface area of Q is 150 sq cm
(2) The distance from one vertex of Q to the catty-corner opposite vertex is 5*sqrt(3)
Kudos for a correct solution.
(1) The total surface area of Q is 150 sq cm
(2) The distance from one vertex of Q to the catty-corner opposite vertex is 5*sqrt(3)
Kudos for a correct solution.
24 Feb 2015, 08:18
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Let x be side of the cube.
1) The total surface area of cube = 6*x^2 =we can use this get x and the volume
2) diagonal connecting opposite corner =x*sqrt(3) =(sqrt(x^2+(xsqrt(2))^2))= 5 sqrt(3) we can use this get x and the volume
answer>> D
1) The total surface area of cube = 6*x^2 =we can use this get x and the volume
2) diagonal connecting opposite corner =x*sqrt(3) =(sqrt(x^2+(xsqrt(2))^2))= 5 sqrt(3) we can use this get x and the volume
answer>> D
24 Feb 2015, 08:25
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The correct answer is D. If we have one side of a cube, we can find the volume: \(V = s^3\)
(1) SA of one side of the cube is \(150/6 = 25\)
SA of one side of a cube is \(s^2\) so \(s^2 = 25\) and \(s = 5\) [Sufficient]
(2) Diagonal of a cube is \(\sqrt{3(s^2)}\) = \(5\sqrt{3}\)
\((5\sqrt{3})^2\) = \(25*3\) = \(75\) so \(3s^2 = 75\)
\(s^2 = 25\) and \(s = 5\) [Sufficient]
(1) SA of one side of the cube is \(150/6 = 25\)
SA of one side of a cube is \(s^2\) so \(s^2 = 25\) and \(s = 5\) [Sufficient]
(2) Diagonal of a cube is \(\sqrt{3(s^2)}\) = \(5\sqrt{3}\)
\((5\sqrt{3})^2\) = \(25*3\) = \(75\) so \(3s^2 = 75\)
\(s^2 = 25\) and \(s = 5\) [Sufficient]
