GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 21 Sep 2018, 09:04

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Quadrilateral RSTU shown above is a site plan for a parking lot in

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Manager
Manager
avatar
Joined: 02 Dec 2012
Posts: 178
Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 14 Dec 2012, 08:53
1
3
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

77% (01:01) correct 23% (00:58) wrong based on 673 sessions

HideShow timer Statistics

Image

Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

(1) RU = 80 meters
(2) TU = \(20\sqrt{10}\) meters

Attachment:
lot.png
lot.png [ 7.64 KiB | Viewed 12296 times ]
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 49300
Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 14 Dec 2012, 09:02
3
Image
Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

Given figure is a trapezoid, thus its area is SW*(ST+RU)/2=60*(45+RU)/2. So, all we need to know to answer the question is the length of RU.

(1) RU = 80 meters. Sufficient.
(2) TU = \(20\sqrt{10}\) meters. Draw altitude from vertex T to RU as shown below:

Image

Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU. Therefore we can find RU=RW+WX+XU. Sufficient.

Answer: D.

Attachment:
trapezoid.png
trapezoid.png [ 12.4 KiB | Viewed 11238 times ]

_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Current Student
User avatar
B
Joined: 12 Oct 2012
Posts: 116
WE: General Management (Other)
GMAT ToolKit User
Re: Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 15 Jul 2016, 05:26
Bunuel wrote:
Image
Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

Given figure is a trapezoid, thus its area is SW*(ST+RU)/2=60*(45+RU)/2. So, all we need to know to answer the question is the length of RU.

(1) RU = 80 meters. Sufficient.
(2) TU = \(20\sqrt{10}\) meters. Draw altitude from vertex T to RU as shown below:
Attachment:
The attachment trapezoid.png is no longer available
Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU. Therefore we can find RU=RW+WX+XU. Sufficient.

Answer: D.


Hi Bunuel,

I am referring to a similar question in Sackmann's Challenge sets (as attached). At first it seemed a simple and a straightforward option D, but the solution (in spoiler) provided in the set says we do not know about the symmetry and hence we cannot use pythagoras theorem to deduce the base of the triangle. I am not sure if this reasoning is correct. Please advise.

Statement (1) is insufficient, but it does help. Knowing ST, combined with
the given length, allows us to use the pythagorean theorem to …and the length
of SW. However, that does no’t give us the entire length of RS unless we knew
the …figure was symmetrical, which we don’t.



Thanks.
Attachments

File comment: Similar Question
Need clarity.PNG
Need clarity.PNG [ 33.38 KiB | Viewed 4063 times ]

Current Student
User avatar
Joined: 18 Oct 2014
Posts: 872
Location: United States
GMAT 1: 660 Q49 V31
GPA: 3.98
GMAT ToolKit User
Re: Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 15 Jul 2016, 06:37
aditi2013 wrote:
Bunuel wrote:
Image
Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

Given figure is a trapezoid, thus its area is SW*(ST+RU)/2=60*(45+RU)/2. So, all we need to know to answer the question is the length of RU.

(1) RU = 80 meters. Sufficient.
(2) TU = \(20\sqrt{10}\) meters. Draw altitude from vertex T to RU as shown below:
Attachment:
trapezoid.png
Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU. Therefore we can find RU=RW+WX+XU. Sufficient.

Answer: D.


Hi Bunuel,

I am referring to a similar question in Sackmann's Challenge sets (as attached). At first it seemed a simple and a straightforward option D, but the solution (in spoiler) provided in the set says we do not know about the symmetry and hence we cannot use pythagoras theorem to deduce the base of the triangle. I am not sure if this reasoning is correct. Please advise.

Statement (1) is insufficient, but it does help. Knowing ST, combined with
the given length, allows us to use the pythagorean theorem to …and the length
of SW. However, that does no’t give us the entire length of RS unless we knew
the …figure was symmetrical, which we don’t.



Thanks.


Hi! aditi2013,

If you notice in question from Sackmann's Challenge sets, length of RO (if UO is perpendicular drawn from U) is not given. Because of which we wouldn't be able to calculate the length of one base.

Whereas, in question by Bunuel, length of RW is given for us to calculate length of base.

Hope I am able to answer your query.
_________________

I welcome critical analysis of my post!! That will help me reach 700+

Manager
Manager
User avatar
B
Status: In the realms of Chaos & Night
Joined: 13 Sep 2015
Posts: 158
Re: Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 15 Jul 2016, 08:37
Walkabout wrote:
Attachment:
lot.png
Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

(1) RU = 80 meters
(2) TU = \(20\sqrt{10}\) meters


Area of Quadrilateral = \(\frac{1}{2}\)*(SW)*(ST+RU)
We have SW & ST - We need RU to solve for area.
Statement 1) gives RU. Sufficient
Statement 2) gives TU - Perpendicular from RU to T should be the same length as SW.
Using Pythagoras therom we can find RU = RW+ST+Ans of Pythagoras theroem. Sufficient.

Ans D)
_________________

Good luck
=========================================================================================
"If a street performer makes you stop walking, you owe him a buck"
"If this post helps you on your GMAT journey, drop a +1 Kudo "


"Thursdays with Ron - Consolidated Verbal Master List - Updated"

Current Student
User avatar
B
Joined: 12 Oct 2012
Posts: 116
WE: General Management (Other)
GMAT ToolKit User
Re: Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 15 Jul 2016, 13:12
Divyadisha wrote:


Hi! aditi2013,

If you notice in question from Sackmann's Challenge sets, length of RO (if UO is perpendicular drawn from U) is not given. Because of which we wouldn't be able to calculate the length of one base.

Whereas, in question by Bunuel, length of RW is given for us to calculate length of base.

Hope I am able to answer your query.[/quote]

Hi Divyadisha,

My query is about statement 1 , which gives us length of ST (we already have height). However, the official solution does not use pythagoras theorem to determine the length of the base, as it mentions that we are not sure about the symmetry.

I am unable to understand that part. Please refer to spoiler in my post and see if it can help to resolve my query.

Regards
Aditi
Director
Director
User avatar
P
Joined: 09 Mar 2016
Posts: 873
Re: Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 21 Apr 2018, 04:42
Bunuel wrote:
Image
Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

Given figure is a trapezoid, thus its area is SW*(ST+RU)/2=60*(45+RU)/2. So, all we need to know to answer the question is the length of RU.

(1) RU = 80 meters. Sufficient.
(2) TU = \(20\sqrt{10}\) meters. Draw altitude from vertex T to RU as shown below:

Image

Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU. Therefore we can find RU=RW+WX+XU. Sufficient.

Answer: D.

Attachment:
trapezoid.png


Hi pushpitkc, hope you are having fantastic gmat weekend :)

this DS question and answers are clear, just want to solve to find XU

Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU.

so we we use pythegorean theorem

\(a^2+b^2 =c^2\)

let XU be \(a\)

\(a^2+60 =20\sqrt{10}\)

\(a^2=20\sqrt{10} - 60\)

can you please explain what am i doing here wrong ? :)
_________________

In English I speak with a dictionary, and with people I am shy.

BSchool Forum Moderator
User avatar
V
Joined: 26 Feb 2016
Posts: 3133
Location: India
GPA: 3.12
Premium Member CAT Tests
Re: Quadrilateral RSTU shown above is a site plan for a parking lot in  [#permalink]

Show Tags

New post 21 Apr 2018, 06:47
1
dave13 wrote:
Bunuel wrote:
Image
Quadrilateral RSTU shown above is a site plan for a parking lot in which side RU is parallel to side ST and RU is longer than ST. What is the area of the parking lot?

Given figure is a trapezoid, thus its area is SW*(ST+RU)/2=60*(45+RU)/2. So, all we need to know to answer the question is the length of RU.

(1) RU = 80 meters. Sufficient.
(2) TU = \(20\sqrt{10}\) meters. Draw altitude from vertex T to RU as shown below:

Image

Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU. Therefore we can find RU=RW+WX+XU. Sufficient.

Answer: D.

Attachment:
trapezoid.png


Hi pushpitkc, hope you are having fantastic gmat weekend :)

this DS question and answers are clear, just want to solve to find XU

Since TX=SW=60 and TU = \(20\sqrt{10}\), then we can find XU.

so we we use pythegorean theorem

\(a^2+b^2 =c^2\)

let XU be \(a\)

\(a^2+60 =20\sqrt{10}\)

\(a^2=20\sqrt{10} - 60\)

can you please explain what am i doing here wrong ? :)


Hi dave13

The mistake you have made is that \(b^2 = 60^2 = 3600\) and \(c^2 = (20\sqrt{10})^2 = 4000\)

Here, \(a^2 + 3600 = 4000\) -> \(a^2 = 4000 - 3600 = 400\) -> \(a = \sqrt{400} = 20\)

Hope that helps you!
_________________

You've got what it takes, but it will take everything you've got

Re: Quadrilateral RSTU shown above is a site plan for a parking lot in &nbs [#permalink] 21 Apr 2018, 06:47
Display posts from previous: Sort by

Quadrilateral RSTU shown above is a site plan for a parking lot in

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Events & Promotions

PREV
NEXT


GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.