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anceer
Joined: 04 Aug 2013
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Location: India
Schools: McCombs '17
GMAT 1: 670 Q47 V35
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WE:Manufacturing and Production (Pharmaceuticals and Biotech)
15 Apr 2016, 06:49
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
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Question Stats:
51% (03:38) correct
49%
(03:37)
wrong
based on 83
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Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage.
A. 16.8%
B. 17.4%
C. 17.9%
D. 18.5%
E. 19.1%
A. 16.8%
B. 17.4%
C. 17.9%
D. 18.5%
E. 19.1%
15 Apr 2016, 07:54
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anceer
Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage.
A. 16.8%
B. 17.4%
C. 17.9%
D. 18.5%
E. 19.1%
A. 16.8%
B. 17.4%
C. 17.9%
D. 18.5%
E. 19.1%
Hi,
Pl share the source
just few points on the Q..
1) Ofcourse 700 level, but the calculations are too complex for a GMAT Q..
2) The method can be tested but may be with numbers that are less calculation intensive
3) Rather it consists of 3 STEPS, which can itself be two-three Qs..
Solution:-
1) first step--
find the number of apples and oranges..
23a + 10b =653, where a>b
10b=653-23a..
so 23a should have units digit as 3 to ensure div by 10b..
so a can be 1,11,21,31..
since a>b, ONLY 21 fits in and b = 17 from equation..
2) second step--
find the CP
apples SP = 23*21= 483.
CP = 483/1.15 = 420
oranges SP = 170
CP = 170/1.25 = 136
total CP= 420+136 = 556
3) Third step
find the Profit %..
By allegation or straight \(\frac{(653-556)}{556} = \frac{97}{556}= 17.44%\)
B
General Discussion
15 Apr 2016, 07:37
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Given: Selling price of an Apple = 23 --> Cost price = 23/1.15 = 20
Selling price of an orange = 10 --> Cost price = 10/1.25 = 8
A > O
23*(A) + 10*(O) = 653
653 - 23*(A) has to be divisible by 10 --> Units digit has to be 0
Values of A can be 1, 11, 21, 31, .... --> 1 cannot be the value
Between 11 and 21, If A = 11, O = 30 --> Not possible
If A = 21, O = 17 --> Possible
Cost price = 20*21 + 8*17 = 420 + 136 = 556
Profit = 653 - 556 = 97
Profit% = (97/556)*100 = 17.4%
Answer: B
P.S: This problem is very calculation intensive as the options are very close. I would guess and move on if I do not arrive at the answer in the stipulated time.
Selling price of an orange = 10 --> Cost price = 10/1.25 = 8
A > O
23*(A) + 10*(O) = 653
653 - 23*(A) has to be divisible by 10 --> Units digit has to be 0
Values of A can be 1, 11, 21, 31, .... --> 1 cannot be the value
Between 11 and 21, If A = 11, O = 30 --> Not possible
If A = 21, O = 17 --> Possible
Cost price = 20*21 + 8*17 = 420 + 136 = 556
Profit = 653 - 556 = 97
Profit% = (97/556)*100 = 17.4%
Answer: B
P.S: This problem is very calculation intensive as the options are very close. I would guess and move on if I do not arrive at the answer in the stipulated time.
