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# rate/distance problem

Author Message
Intern
Joined: 28 Jun 2008
Posts: 39

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15 Jun 2009, 10:59
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

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hi guys was wondering if anyone had a method for this problem:

A cetain car averages 25 miles of gasoline when driven in the city and 40 miles per gallon when driven on the highway. According to these rates, which of the following is closest to the number of miles per gallon that the car averages when it is driven 10 miles in the city and then 50 miles on the highway?

A. 28
B. 30
C. 33
D. 36
E. 38

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Current Student
Joined: 03 Aug 2006
Posts: 110

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15 Jun 2009, 11:34
1
This is a variation on Rate, Time and Distance problem
Rate x Time = Distance.
Here it is
Mileage (m) x Gallons (g) = Distance (d)

Solution:
For City Driving --- 1
$$m1 = 25mpg (given)$$
$$g1 = not given$$
$$d1 = 10 (given)$$

Calculate g1
$$g1=\frac{d1}{m1}=\frac{10}{25}$$

For Highway Driving ---2
$$m2 = 40mpg (given)$$
$$g2 = not given$$
$$d2 = 50 (given)$$

Calculate g2
$$g2=\frac{d2}{m2}=\frac{50}{40}$$

Total gallons of gas
$$g= g1+g2 = \frac{10}{25} + \frac{50}{40}$$

Total distance
$$d= 10+50 = 60$$

Calculate m
$$m=\frac{d}{g}$$

$$=\frac{60}{\frac{10}{25} + \frac{50}{40}}$$

$$= \frac{60}{\frac{1650}{1000}}$$

$$= 60\times\frac{1000}{1650}$$

$$= 36.36$$

--== Message from the GMAT Club Team ==--

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This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Non-Human User
Joined: 09 Sep 2013
Posts: 9163

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06 Aug 2018, 07:49
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: rate/distance problem &nbs [#permalink] 06 Aug 2018, 07:49
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