Bunuel wrote:

S and T are two water pumps that run at constant rates. If pump T pumped alone, how many more hours would it take for it to finish pumping a large container than it would take for pump S to accomplish the same task by itself?

(1) When both the water pumps work together, they finish pumping a large container in 2/3 rd the time it takes for pump S to finish the task alone.

(2) Pump T is capable of pumping a large container in twice the time that it takes pump S to accomplish the same task alone.

Kudos for a correct solution.

Not sure, but here what you can read out of the Statements:

1: Combined Time is 2/3x where x is the time of Pump S. > IS because there is no information about Pump T to S itself.

2: Pump T needs twice the time of Pump S. Alone it is insufficient.

Statement 1 + 2:

Combined Time 2/3X Hours

Pump S Time: X Hours

Pump T Time: 2X Hours

To solve, we needed to have at least X. Like this, there is no way to figure out the hours.

Answer E

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