Bunuel wrote:
S and T are two water pumps that run at constant rates. If pump T pumped alone, how many more hours would it take for it to finish pumping a large container than it would take for pump S to accomplish the same task by itself?
(1) When both the water pumps work together, they finish pumping a large container in 2/3 rd the time it takes for pump S to finish the task alone.
(2) Pump T is capable of pumping a large container in twice the time that it takes pump S to accomplish the same task alone.
Kudos for a correct solution.
Not sure, but here what you can read out of the Statements:
1: Combined Time is 2/3x where x is the time of Pump S. > IS because there is no information about Pump T to S itself.
2: Pump T needs twice the time of Pump S. Alone it is insufficient.
Statement 1 + 2:
Combined Time 2/3X Hours
Pump S Time: X Hours
Pump T Time: 2X Hours
To solve, we needed to have at least X. Like this, there is no way to figure out the hours.
Answer E
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