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Difficulty:
65%
(hard)
Question Stats:
44%
(01:29)
correct 56%
(01:00)
wrong
based on 16
sessions
History
Date
Time
Result
Not Attempted Yet
Set X is given by {a, 2a, 3a, 4a, 5a} where ‘a’ is a positive integer. If element ‘a’ in Set X is replaced by ‘b’ and b < a, then which of the following must be true?
I. Mean would not change.
II. Median would not change.
III. Standard deviation would not change
A. I only
B. II only
C. III only
D. Both I and II
E. Both II and III
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We can answer by looking the options. If suppose mean changes, then definitely standard deviation would change and vice versa. But in options I & III together are not given. So definitely D & E are not the answer. Similar to that A & C can't be the answer also. So only option remaining is B
Set X is given by {a, 2a, 3a, 4a, 5a} where ‘a’ is a positive integer. If element ‘a’ in Set X is replaced by ‘b’ and b < a, then which of the following must be true?
I. Mean would not change.
II. Median would not change.
III. Standard deviation would not change
A. I only
B. II only
C. III only
D. Both I and II
E. Both II and III
Show more
With values this small, try numbers if not sure. It's very quick.
Only first term, a, changes, not the multiples of a. Otherwise prompt would say "If [EACH] element ‘a’ in Set X is replaced by . . ."
a = 2 Set 1: (2, 4, 6, 8, 10)
b = 1 Set 2: (1, 4, 6, 8, 10)
MUST be true?
I. Mean would not change. Set 1 mean = 6 Set 2 mean = 29/5 = 5.8 FALSE
II. Median would not change. Set 1 median = 6 Set 2 median = 6 TRUE
III. Standard deviation would not change
Either remember: If you add or subtract the same number to every number in original set, SD does not change. If you change just one number, SD changes. OR
SD, roughly: how tightly are all the values clustered around the mean? Look at values on the right side of the mean that don't change (here, numbers 8 and 10).
In Set 1, mean is 6. Value 8 is exactly 2 away from mean, 10 is exactly 4 away from mean
In Set 2, mean is 5.8. Values 8 and 10 are farther from 5.8 than they are from 6. The numbers now are "clustered" differently around (in test cases farther from) the mean. FALSE
Answer B
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.