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# Sharla is a better chess player than Marcus. Marcus is a better ches

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SVP
Joined: 12 Dec 2016
Posts: 1710
Location: United States
GMAT 1: 700 Q49 V33
GPA: 3.64
Sharla is a better chess player than Marcus. Marcus is a better ches  [#permalink]

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10 Mar 2018, 14:03
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65% (hard)

Question Stats:

48% (01:26) correct 52% (01:30) wrong based on 117 sessions

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Sharla is a better chess player than Marcus.
Marcus is a better chess player than Evelyn.
Olivia routinely beats Evelyn at chess.

What is the likely outcome if Sharla and Olivia play a game of chess?

A. Olivia will beat Sharla
B. Sharla will beat Olivia
C. The game will end in a draw
D. Olivia will decide not to play Sharla because she is intimidated
E. The two women will decide not to play chess at all

Testguide
PS Forum Moderator
Joined: 16 Sep 2016
Posts: 314
GMAT 1: 740 Q50 V40
Re: Sharla is a better chess player than Marcus. Marcus is a better ches  [#permalink]

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12 Mar 2018, 02:59
chesstitans wrote:
Sharla is a better chess player than Marcus.
Marcus is a better chess player than Evelyn.
Olivia routinely beats Evelyn at chess.

What is the likely outcome if Sharla and Olivia play a game of chess?

A. Olivia will beat Sharla
B. Sharla will beat Olivia
C. The game will end in a draw
D. Olivia will decide not to play Sharla because she is intimidated
E. The two women will decide not to play chess at all

Testguide

I made the following logical assumption - if a play is better at chess - he or she "always" wins the game when playing against a player who is not as good as them.

A > B is used to indicate A is better than B.

Sharia > Marcus
Marcus > Evelyn
Olivia routinely beats Evelyn.

So Olivia $$>=$$ Evelyn

Here : Sharia is the strongest among at least Marcus and Evelyn.

Since Olivia is only "routinely" beating Evelyn and not always - it is safe to assume that Olivia is not as better than Evelyn as is Sharia ( who is better than a person already better than Evelyn )

So Sharia > Olivia.
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Joined: 14 Feb 2018
Posts: 374
Re: Sharla is a better chess player than Marcus. Marcus is a better ches  [#permalink]

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12 Mar 2018, 06:15
1
Gladiator59 wrote:
chesstitans wrote:
Sharla is a better chess player than Marcus.
Marcus is a better chess player than Evelyn.
Olivia routinely beats Evelyn at chess.

What is the likely outcome if Sharla and Olivia play a game of chess?

A. Olivia will beat Sharla
B. Sharla will beat Olivia
C. The game will end in a draw
D. Olivia will decide not to play Sharla because she is intimidated
E. The two women will decide not to play chess at all

Testguide

I made the following logical assumption - if a play is better at chess - he or she "always" wins the game when playing against a player who is not as good as them.

A > B is used to indicate A is better than B.

Sharia > Marcus
Marcus > Evelyn
Olivia routinely beats Evelyn.

So Olivia $$>=$$ Evelyn

Here : Sharia is the strongest among at least Marcus and Evelyn.

Since Olivia is only "routinely" beating Evelyn and not always - it is safe to assume that Olivia is not as better than Evelyn as is Sharia ( who is better than a person already better than Evelyn )

So Sharia > Olivia.

Hi,

But routinely also means regularly. So the safest would be to assume both are equally good, since no other information is given as to who is better among them.

I would go with C.

Sent from my Lenovo K53a48 using GMAT Club Forum mobile app
PS Forum Moderator
Joined: 16 Sep 2016
Posts: 314
GMAT 1: 740 Q50 V40
Re: Sharla is a better chess player than Marcus. Marcus is a better ches  [#permalink]

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12 Mar 2018, 06:59
SonalSinha803 wrote:
Gladiator59 wrote:
chesstitans wrote:
Sharla is a better chess player than Marcus.
Marcus is a better chess player than Evelyn.
Olivia routinely beats Evelyn at chess.

What is the likely outcome if Sharla and Olivia play a game of chess?

A. Olivia will beat Sharla
B. Sharla will beat Olivia
C. The game will end in a draw
D. Olivia will decide not to play Sharla because she is intimidated
E. The two women will decide not to play chess at all

Testguide

I made the following logical assumption - if a play is better at chess - he or she "always" wins the game when playing against a player who is not as good as them.

A > B is used to indicate A is better than B.

Sharia > Marcus
Marcus > Evelyn
Olivia routinely beats Evelyn.

So Olivia $$>=$$ Evelyn

Here : Sharia is the strongest among at least Marcus and Evelyn.

Since Olivia is only "routinely" beating Evelyn and not always - it is safe to assume that Olivia is not as better than Evelyn as is Sharia ( who is better than a person already better than Evelyn )

So Sharia > Olivia.

Hi,

But routinely also means regularly. So the safest would be to assume both are equally good, since no other information is given as to who is better among them.

I would go with C.

Sent from my Lenovo K53a48 using GMAT Club Forum mobile app

Even by that interpretation Olivia would only be equal to someone who is better than Evelyn ( i.e Marcus).

Since we are given Sharia > Marcus and by your logic -> Marcus = Olivia so....

Sharia > Olivia.

Best,
Gladi
Intern
Joined: 14 Sep 2017
Posts: 11
Re: Sharla is a better chess player than Marcus. Marcus is a better ches  [#permalink]

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12 Mar 2018, 13:06
chesstitans wrote:
Sharla is a better chess player than Marcus.
Marcus is a better chess player than Evelyn.
Olivia routinely beats Evelyn at chess.

What is the likely outcome if Sharla and Olivia play a game of chess?

A. Olivia will beat Sharla
B. Sharla will beat Olivia
C. The game will end in a draw
D. Olivia will decide not to play Sharla because she is intimidated
E. The two women will decide not to play chess at all

Testguide

Although I answered correctly, this is a bad question and not at all like GMAC Qs. It is NOT logically provable.
Re: Sharla is a better chess player than Marcus. Marcus is a better ches &nbs [#permalink] 12 Mar 2018, 13:06
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# Sharla is a better chess player than Marcus. Marcus is a better ches

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