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08 Dec 2014, 06:23
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C
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Difficulty:
35%
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Question Stats:
62% (01:21) correct
38%
(01:24)
wrong
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Six students - 3 boys and 3 girls - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?
A) 12
B) 36
C) 72
D) 240
E) 720
Source: Chili Hot GMAT
A) 12
B) 36
C) 72
D) 240
E) 720
Source: Chili Hot GMAT
08 Dec 2014, 06:41
Kudos
Bookmarks
in order not to have two boys or two girls next to one another, we must make an alternate sitting arrangement. (B-G-B-G-B-G) or (G-B-G-B-G-B).
Total ways = 2C1*3!*3!
=2*6*6
=72
Ans - C
Total ways = 2C1*3!*3!
=2*6*6
=72
Ans - C
08 Dec 2014, 07:20
Kudos
Bookmarks
Six students - 3 boys and 3 girls - are to sit side by side for a makeup exam. How many ways could they arrange themselves given that no two boys and no two girls can sit next to one another?
A) 12
B) 36
C) 72
D) 240
E) 720
The boys (B) and girls(G) can either be arranged as BGBGBG or GBGBGB.
Within the arrangement BGBGBG or GBGBGB, the boys can be arranged 3! ways and girls can be arranged 3! ways.
Therefore total number of ways boys and girls can be arranged = 2*3!*3!= 72 ways
Answer: C
A) 12
B) 36
C) 72
D) 240
E) 720
The boys (B) and girls(G) can either be arranged as BGBGBG or GBGBGB.
Within the arrangement BGBGBG or GBGBGB, the boys can be arranged 3! ways and girls can be arranged 3! ways.
Therefore total number of ways boys and girls can be arranged = 2*3!*3!= 72 ways
Answer: C
