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Solution X, which is 50% alcohol, is combined with solution Y, which
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10 Apr 2018, 21:50
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Solution X, which is 50% alcohol, is combined with solution Y, which is 30% alcohol, to form 16 liters of a new solution that is 35% alcohol. How much of solution Y is used?
A. 4 liters B. 6 liters C. 8 liters D. 10 liters E. 12 liters
Re: Solution X, which is 50% alcohol, is combined with solution Y, which
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11 Apr 2018, 00:42
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You are given : Y------------Mix-------------X 30%----------35%------------50%
Therefore the proportion of Y:X is 3:1.
For every 4 liters of mixture you have 3 liters of Y and 1 liter of X. In total you have 16 liters, which means that you have : 3x4 = 12 liters of Y and 4 liters of X.
Solution X, which is 50% alcohol, is combined with solution Y, which
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11 Apr 2018, 08:48
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Bunuel wrote:
Solution X, which is 50% alcohol, is combined with solution Y, which is 30% alcohol, to form 16 liters of a new solution that is 35% alcohol. How much of solution Y is used?
A. 4 liters B. 6 liters C. 8 liters D. 10 liters E. 12 liters
let y=amount of solution Y used .5(16-y)+.3y=.35*16 y=12 liters E
Solution X, which is 50% alcohol, is combined with solution Y, which
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11 Apr 2018, 09:08
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Bunuel wrote:
Solution X, which is 50% alcohol, is combined with solution Y, which is 30% alcohol, to form 16 liters of a new solution that is 35% alcohol. How much of solution Y is used?
A. 4 liters B. 6 liters C. 8 liters D. 10 liters E. 12 liters
This weighted average formula is easy to use:
(% X)(Vol X) + (% Y)(Vol Y) = (% of X+Y)(Vol X+Y)
Solution X = 50 percent alcohol = .50 Solution Y = .30 alcohol Total volume of resultant solution: 16 = X+Y Let Y's volume = \(y\) X's volume = \(16 - y\)
Re: Solution X, which is 50% alcohol, is combined with solution Y, which
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13 Apr 2018, 03:42
Bunuel wrote:
Solution X, which is 50% alcohol, is combined with solution Y, which is 30% alcohol, to form 16 liters of a new solution that is 35% alcohol. How much of solution Y is used?
A. 4 liters B. 6 liters C. 8 liters D. 10 liters E. 12 liters
Let, x = amount solution X mixed y = amount solution Y mixed x+y = 16.........(A)
Using "Amount = concentration * volume " and the data given we get following eqn:
50x + 30y = 35 (x+y)
Solving this eqn we get: y=3x ...........(B)
With help of eqn (A) and (B) we get y = 12 (Option E)
Re: Solution X, which is 50% alcohol, is combined with solution Y, which
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28 Aug 2018, 12:06
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Bunuel wrote:
Solution X, which is 50% alcohol, is combined with solution Y, which is 30% alcohol, to form 16 liters of a new solution that is 35% alcohol. How much of solution Y is used?
A. 4 liters B. 6 liters C. 8 liters D. 10 liters E. 12 liters
When solving mixture questions, I find it useful to sketch the solutions with the ingredients SEPARATED:
Since we want to determine the volume of solution Y needed, let's... Let y = volume (in liters) of solution Y needed This means 16 - y = volume (in liters) of solution X needed (since the combined volume of both amounts is 16 liters)
So, we get:
Now let's determine the volume of alcohol in each container.
Solution Y is 30% alcohol. We have y liters of solution Y. So, the volume of alcohol = 0.3y
Solution X is 50% alcohol. We have 16 - y liters of solution X. So, the volume of alcohol = 0.5(16 - y) = 8 - 0.5y
The combined solution is 35% alcohol. There are 16 liters of this solution. So, the volume of alcohol = 0.35(16) = 5.6
So, our sketch looks like this:
At this point, we can focus on the volume of alcohol in each container. We know that: (volume of alcohol in 1st container) + (volume of alcohol in 2nd container) = volume of alcohol in combined solution. In other words: 0.3y + (8 - 0.5y) = 5.6 Simplify: 8 - 0.2y = 5.6 Subtract 8 from both sides to get: -0.2y = -2.4 Solve: y = 12
Re: Solution X, which is 50% alcohol, is combined with solution Y, which
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30 Aug 2018, 17:57
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Bunuel wrote:
Solution X, which is 50% alcohol, is combined with solution Y, which is 30% alcohol, to form 16 liters of a new solution that is 35% alcohol. How much of solution Y is used?
A. 4 liters B. 6 liters C. 8 liters D. 10 liters E. 12 liters
We start with x liters of a solution that is 50% alcohol. We add to it y liters of a solution that is 30% alcohol. The result is (x + y) liters of a solution that is 35% alcohol. We can create the equations: